- #1

vkash

- 318

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Determine the value of integral from -pie to pie [2x(1+sin(x)]/[1+cos(x)*cos(x)]

sorry i can't provide it's answer because i am not able to tex tags i tried a lot but every time i am getting error. that doesn't print things as it should. see this(next line) where am i wrong

[tex]\frac{2x(1+sinx)}{1+cos^2x}[\tex]. did you see it's effect.?

My steps of solving question are.

(1) change x by -x(property)

(2)put cos(x)=t upper and lower limmit will became equal so it's answer should zero but it's answer is not zero.

It's answer is pie square. i have reached to pie square. How. After first step the integration can also be written as limit 0 to pie(do also twice of it). After that i solve it ans reached to answer pie square.

sorry i can't provide it's answer because i am not able to tex tags i tried a lot but every time i am getting error. that doesn't print things as it should. see this(next line) where am i wrong

[tex]\frac{2x(1+sinx)}{1+cos^2x}[\tex]. did you see it's effect.?

My steps of solving question are.

(1) change x by -x(property)

(2)put cos(x)=t upper and lower limmit will became equal so it's answer should zero but it's answer is not zero.

It's answer is pie square. i have reached to pie square. How. After first step the integration can also be written as limit 0 to pie(do also twice of it). After that i solve it ans reached to answer pie square.

**Afterall my question is why it' answer came zero if i put cos(x)=t in first case.**

where can i found the pdf or htm file containing the way of using tex or any other such things.where can i found the pdf or htm file containing the way of using tex or any other such things.

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