Where Did I Go Wrong in My Concentration Problem?

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The discussion revolves around a chemistry problem involving the production of lithopone from barium sulfate and zinc sulfide. The user calculates the moles of BaS and ZnSO4, identifying ZnSO4 as the limiting reagent. However, there is confusion regarding the calculation of the mass of lithopone produced. Other participants suggest verifying calculations and emphasize the need to find the masses of both precipitates to determine the final mass. The correct answer to the problem is stated as 1.93 grams, although there is uncertainty about this figure.
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Homework Statement


hey guys I've got a problem, could you tell us where i went wrong

Lithopone is a brilliant white pigment used in water-based interior paints. It is a mixture of barium sulfate and zinc sulfide produced by the reaction
BaS(aq) + ZnSO4(aq) ZnS(s) + BaSO4(s)
What mass of lithopone in grams (to 3 significant figures) is produced in the reaction of 227 mL of 0.257 M ZnSO4 and 325 mL of 0.280 M BaS?

MY WORKED SOLUTION"
Mole of BaS=0.280*0.325=0.091mole
mole of ZnSO4=0.0257*0.277=0.0712moles <therefore this is limiting

i don't know what i should take the molarmass of to work out the mass?

ANSWER IS 1.93 grams

anyhelp would be GREATFULLY appreciated.



Homework Equations





The Attempt at a Solution

 
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geffman1 said:
mole of ZnSO4=0.0257*0.277=0.0712moles <therefore this is limiting

Check your math. Check it twice, as abvious typo is not the error I am thinking about.

ANSWER IS 1.93 grams

No, 1.93g is not the answer. Probably typo again.

You are on the right track. Find limiting reagent, find moles of both solids that precipitated, find their masses - and as you are looking for a precipitate mass, add them.
 
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