Where does the plane exist in this parallel axis theorem?

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Homework Help Overview

The discussion revolves around the parallel axis theorem in the context of a geometric sketch involving an unlabelled rectangular area. Participants are exploring the implications of the theorem and the orientation of the area in relation to the plane of the sketch.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to clarify the location and orientation of the area referenced in the theorem, questioning whether it is perpendicular or parallel to the plane of the sketch.

Discussion Status

The discussion is ongoing, with multiple participants reiterating the question of the area’s orientation and confirming that it exists within the plane, but no consensus has been reached on the specifics of its relationship to the plane.

Contextual Notes

There is a focus on the unlabelled rectangular area and its positioning, with some ambiguity regarding its orientation in relation to the plane, which may affect the application of the parallel axis theorem.

Benjamin_harsh
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Homework Statement
MOI of an area w.r.t any axis in its plane is equal to the MOI of the
area w.r.t a parallel centroidal axis plus the product of
area and square of the distance between the two axes.
Relevant Equations
##I_{AB} = I_{GXX} + A.(y^{2})##
245272


##I_{AB} = I_{GXX} + A.(y^{2})##

Same applies to CD;
##I_{CD} = I_{GYY} + A.(x^{2})##

In the above statement, "any axis in its plane" where does the plane exist in this sketch?
 
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The area is that unlabelled rectangular figure, and it's in the plane of the page.
 
NascentOxygen said:
The area is that unlabelled rectangular figure, and it's in the plane of the page.
Is that area perpendicular to the plane or parallel to the plane?
 
Benjamin_harsh said:
Is that area perpendicular to the plane or parallel to the plane?
The area is within the plane. It is that portion of the plane enclosed by four lines.
 
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