Where is the center of mass of a flat triangular plate with given dimensions?

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Homework Help Overview

The discussion revolves around finding the center of mass of a flat triangular plate with specified dimensions: a height of 17.3 cm and a base of 10 cm. Participants are examining the mathematical approach to determine the coordinates of the center of mass using integrals.

Discussion Character

  • Mathematical reasoning, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to calculate the area and the coordinates of the center of mass using integrals, but expresses confusion over discrepancies between their results and those provided in a textbook. Other participants question the correctness of the integral setup and the orientation of the triangle.

Discussion Status

The discussion is ongoing, with participants providing feedback on the original poster's integral expressions and clarifying the triangle's orientation. There is a focus on ensuring the correct interpretation of the triangle's dimensions and layout.

Contextual Notes

Some participants note potential issues with the orientation of the triangle relative to the coordinate axes, which may affect the calculations. The original poster's confidence in their method contrasts with the textbook's answers, indicating a need for further exploration of assumptions and setups.

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Find the x and y coordinates of the center of mass of a flat triangular plate of a height H =17.3cm and a base B = 10 Cm


Homework Equations



Area = A = 1/2bh
x = 1/A ∫ x(f(x))
y = 1/A ∫ 1/2((f(x)^2)


The Attempt at a Solution



Area = 1/2(10)(17.3) = 86.5

f(x) = 17.3-1.73x or 17.3-173/100x
... this represents the equation for the line of the hypt. of the triangle, with its y intercept at 17.3 and its x intercept at 10, and a slope of 17.3/10


All interals from 0 to 10

x = 1/86.5 ∫x(17.3-1.73x) = 3.333333cm
y = 1/86.5 ∫1/2((17.3-1.73x)^2) = 5.7666667cm



I've done this problems like these tons of time in calc and on my homework for physics, using this same method... but according to the answers in the book I'm getting this question wrong

their answer says the x,y coordinates are (6.67cm, 11.5cm)

I'm not really sure what I'm doing wrong
Please point out any mistakes I may have made
and the right direction I should be heading in

Thank you !
 
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Is there an accompanying picture? The way the base and height are laid out would effect where the center is.
 
Your integral expressions are not properly written. Are you integrating with respect to x or y?
 
The triangle is a right triangle
The 90 degree angle is situated at the orgin... so the height follows up the y-axis or x= o
and the base follows the x-axis at y=0... more or less the height and base make the x and y axis

I intergrating with repect to x, that's why i created an equation from the line of the hypt. of the triangle. The line/equation will make a triangle with the x and y axis... or the base and height... y intercept = height of 17.3 and x intercept = base of 10


hoped I helped in clearing up questions about my approach
 
According to the coordinates of the cg from your book, the base of the triangle is located at y = 17.3 and the other side of the triangle adjacent to the right angle is x = 10. Are you sure of the orientation of your triangle w.r.t. the origin?
 

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