i don't have a solution for now since i can't figure out how to solve for d1 and d2
rize said:d1 is the distance of q1 from the neutral point , d2 is the distance of q2 from the neutral point
* q1-------------------------------q2 * |<----------->|
dkkrizka said:Just try to look at it like a 1D problem. Along a line joining the two charges there will be a point where the sum of the fields is 0. Also using rules of repulsion/attraction for charges, you can figure out that the point will NOT be between the two charges. So the distance from one charge is d1, and the distance from the second charge is 2+d1.
Drawing a picture always helps. :)
Just use your rules of repulsion/attraction between two charges. If the test change was placed between the two charges in the question, The negative would attract it left and the positive would push it away, towards the left. No matter how you add them, it would result in a vector pointing left.rize said:how can it happen that it won't be between the charges?
rize said:https://www.physicsforums.com/latex_images/16/1629068-1.png
why is it d+2.. ? where did the 2 come from?
The neutral point in an electrostatic field is typically located at the center of the field, where the electric field strength is zero.
The neutral point can be determined by finding the point where the sum of the electric field vectors from all charges in the field is equal to zero.
No, the location of the neutral point in an electrostatic field can vary depending on the distribution and magnitude of charges in the field.
Yes, the neutral point can be located outside of the boundaries of an electrostatic field if there are charges present outside of the field that influence the electric field within it.
The neutral point is important in electrostatics because it represents a point of equilibrium where the electric field strength is zero. This can have implications for the behavior of charged particles and the overall stability of the system.