Where the total electric field is equal to zero?

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SUMMARY

The discussion focuses on determining the point along the x-axis where the total electric field is zero due to two point charges: -2.5 µC and 6.0 µC, which are 1.0 m apart. The user correctly applies the equations for electric field (E=F/q) and force (F=K(Q*q)/d²) to derive the net electric field equation. The solution reveals that the electric field is zero at a point 1.82 m to the left of the 6.0 µC charge, while the other potential solution was disregarded as it lies between the two charges where fields cannot cancel.

PREREQUISITES
  • Understanding of electric field concepts and equations
  • Familiarity with Coulomb's Law (F=K(Q*q)/d²)
  • Knowledge of quadratic equations and their solutions
  • Basic principles of superposition in electric fields
NEXT STEPS
  • Study the concept of electric field superposition in detail
  • Learn how to solve quadratic equations effectively
  • Explore the implications of electric field direction and magnitude
  • Investigate the behavior of electric fields in multi-charge systems
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Students studying electromagnetism, physics educators, and anyone seeking to understand electric field interactions between point charges.

barrett
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Homework Statement


Two point charges of -2.5 µC and 6.0 µC lying along the x-axis are 1.0 m apart. Locate the point (other than infinity) at which the total electric field is zero.

Homework Equations


I was thinking: E=F/q
and
F=K (Q x q)/d^2
But I'm not quite sure how to use them.



The Attempt at a Solution


Using the second equation I found F to be -.135. But I don't think that's right, and then when plugging that into the E=F/q. E would have to be zero, since I'm trying to find where the total electric field is zero? Then there's no solutions other than infinity, are there? And what exactly is q in the first equation. I really have no idea what's going on here.
 
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If the electric field is zero, is it the case that the force is also zero? So find the point(s) where the net electric force or field is zero.
 
I found an example online and I think I substituted the right numbers in for this problem, is this how it would be solved? (I didn't understand the equation below and where it came from: KQ/x²-2.4KQ/(x+1.00)²)

Enet=Esub1 + Esub2 = KQ/x²-2.4KQ/(x+1.00)²
KQ/x²-2.4KQ/(x+1.00)²

The Ks and Qs cancel out leaving:
1/x² = 2.4/(x+1.00)²

And then get it into a quadratic:
1.4x² - 2x -1=0

And find it to be 1.82 m to the left of charge Q. I ignored the other root, -.39m because that would be between the two charges where the fields cannot cancel out.
Am I on the right track?
 

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