Where to find formulas for acceleration of compressed steel tubes

Click For Summary
SUMMARY

This discussion focuses on the formulas for calculating the maximum acceleration of compressed steel tubes when released underwater. Key considerations include the method of compression (axial, radial, etc.) and the effects of water drag on motion. The conversation emphasizes the importance of using accurate equations for fluid dynamics and suggests that engineers often rely on physical models for testing rather than theoretical calculations. The simplest approach involves using the drag equation for a cylinder and the rocket equation for thrust generated by compressed air.

PREREQUISITES
  • Understanding of fluid dynamics and drag forces
  • Familiarity with basic physics concepts such as thrust and acceleration
  • Knowledge of mechanical properties of materials, specifically steel
  • Experience with mathematical modeling and equations related to motion
NEXT STEPS
  • Research the drag equation for cylindrical objects in fluid dynamics
  • Study the rocket equation to understand thrust generation from compressed gases
  • Explore the effects of buoyancy on submerged objects
  • Investigate mechanical oscillations and relaxation in compressed materials
USEFUL FOR

Engineers, physicists, and researchers involved in fluid dynamics, mechanical design, and materials science will benefit from this discussion, particularly those working on applications involving underwater dynamics and material behavior under compression.

mhl
Messages
6
Reaction score
0
Hi all

Looking for simple formulas to describe maximum acceleration of steel tubes when tubes are compressed and suddenly released when submerged in water (dont know if the water does anything else than supply buoyancy).

Please, also feel free to comment freely on the topic and formulas you might state...

Hope you can help...


thanks

mhl
 
Engineering news on Phys.org
Compressed how? Axially, radially, filled with compressed air, etc. etc. Your description of the problem isn't sufficient
to even begin to understand the question let alone answer it.

As for simple equations, where are simple equations, and
then there are usefully correct equations; the two aren't
always overlapping when you're dealing with something
like drag due to motion in water. There's a reason that
engineers often build scale models of things and test them
"for real" in water tanks rather than relying on the accuracy
of estimates from fluid flow / drag calculations; it's
often easier to build and test the thing rather than model
it sufficiently accurately even with complex equations and
computer models.

If it's just a question of axial acceleration of a tube through
water given a certain 'rocket' thrust from compressed air
inside the tube released from an axial nozzle in the rear,
then you could probably find a good simple formula for
the drag of a cylinder of a given size in water, and the
thrust will just be the simple rocket equation due to
the momentum of the release of the gas given a certain
escaping gas flow rate due to the pressure differential of
the gas vs. the water and the size/performance of the
nozzle the gas escapes through. That's about as simple
as that gets, pretty simple to estimate with simple
math and a notepad, but still not trivial.

Unless you're talking about the mechanical relaxation /
oscillation / 'springing' / ringing (like a bell) /
expansion (like a bellows) of a structurally compressed tube
under water in which case, well, good luck, that's likely
a lot more complicated due to (in)elasticity, friction,
drag, heat, possibly turbulent fluid flow, etc. etc.

The simplest case would be like letting go of a coiled
tube spring underwater in which case you're back to
estimating the cylinder's drag and the the evolution of
the 'spiringing away' based on the water's drag and the
F=mx tension in the spring and how long the spring will
be able to push against its dock...
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 45 ·
2
Replies
45
Views
7K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 2 ·
Replies
2
Views
25K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 39 ·
2
Replies
39
Views
16K
  • · Replies 114 ·
4
Replies
114
Views
7K