Where to Find Free Help for Solving Physics Questions Online?

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Homework Help Overview

The discussion revolves around finding assistance for physics questions, with a focus on electrostatics and related concepts. Participants are exploring the nature of electrostatic forces and the derivation of the electric field equation E = v/d.

Discussion Character

  • Exploratory, Conceptual clarification

Approaches and Questions Raised

  • Participants inquire about the definition of electrostatic forces and seek clarification on deriving the equation E = v/d. There is also a suggestion to limit questions to one per thread for clarity.

Discussion Status

The discussion is ongoing, with participants raising questions and suggestions about the format and clarity of the inquiries. Some guidance on structuring questions has been offered, but no consensus has been reached regarding the specific physics concepts.

Contextual Notes

There are concerns about the clarity of the handwritten questions, which may hinder understanding. Additionally, the discussion includes a reference to the conductive nature of spheres in a physics problem, which is under consideration.

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Homework Statement



i have uploaded physics questions here.

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The Attempt at a Solution

 

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Physics news on Phys.org
someone can help me solve?
 
I think you should limit it to one question per thread, so that the answers are also understandable and of help to others who may be perusing this forum. I also think the handwriting is too difficult to readily discern the question.

(23) I reckon the answer may lie in the fact that the spheres are conductive. Normally, this sort of question relates to the use of insulating spheres, where the situation is equivalent to a point charge located at the centre of each sphere. But in your question, the spheres are not insulating. How may this change things?
 
1)what is electrostatic forces?
2) how to derive E = v /d ?
 
blueskye said:
1)what is electrostatic forces?
2) how to derive E = v /d ?
Good sites for keen learners to find such information are http://www.google.com"
 
Last edited by a moderator:

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