Estimate for the change in range for a proton

  • #1
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Homework Statement



I've uploaded the question in the attached file.

Homework Equations



R ∝ 1/p
R ∝ M/z2

The Attempt at a Solution



I don't understand what is in my lecture notes. What equations do I need to attempt this question? Thank you.
 

Attachments

Answers and Replies

  • #2
PeterDonis
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I don't understand what is in my lecture notes. What equations do I need to attempt this question?
We can't give any assistance unless you can show us some attempt at a solution. Also, just saying you don't understand what's in your lecture notes is way too vague. We need specifics about what equations or statements you don't understand. If your lecture notes or textbook are available online, please give a reference.
 
  • #3
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As Peter has said, we can't help until we see your work.

We need to know some context too:

Is this a high school or college assignment? what class are you taking? what book are you using? ...
 
  • #4
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Hi, I can't really put my lecture notes on here - they're too long to post and it would identify the university. I've taken a screenshot of the section of the notes where those equations are from. It's a past paper question on the subject of radiaton protection. I don't have a book so any guidance would be valuable.

https://image.ibb.co/eeJgXJ/notes.jpg

There is a formula on the following website, is this along the right lines?

http://www.kayelaby.npl.co.uk/atomic_and_nuclear_physics/4_5/4_5_1.html
 
Last edited:
  • #5
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Attempt at the question:

R(B) = [M/Z2] Rp(B)

Propton range versus energy of photon values gained from this graph: https://books.google.co.uk/books?id...EIazAH#v=onepage&q=proton range g/cm2&f=false

1 MeV photon in Al = 0.01 g/cm2
1 MeV photon in Pb = 0.03 g/cm2

R(B) = 27/132 (0.01 g/cm2) = 1.598x10-3 g/cm2
R(B) = 208/822 (0.03 g/cm2) = 9.280x10-4 g/cm2

Change in R = 1.598x10-3 g/cm2 - 9.280x10-4 g/cm2 = 6.7x10-4 g/cm2
 
  • #6
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Bump.
 

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