Where to Place a Negative Charge for Zero Electric Field at the Origin?

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Homework Help Overview

The problem involves determining the position of a negative charge that will create a net electric field of zero at the origin, given a positive charge located on the x-axis. The subject area pertains to electrostatics and electric fields.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the placement of the negative charge relative to the positive charge and explore the concept of electric fields produced by multiple charges. There are questions about the application of the electric field equation and the principle of superposition.

Discussion Status

The discussion is ongoing, with participants attempting to clarify the relationship between the two charges and how to calculate the resulting electric field. Some guidance has been provided regarding the principle of superposition, but no consensus has been reached on the exact placement of the negative charge.

Contextual Notes

Participants are navigating the constraints of the problem, including the specific values of the charges and their locations, as well as the requirement for the net electric field to be zero at the origin.

Bearbull24.5
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Homework Statement


A 40 uC charge is placed on x-axis at x=4cm. Where should a negative 60 uC charge be placed to produce a net electric field of zero at the origin?


Homework Equations



Fe=Ke((q1*q2)/r^2)

The Attempt at a Solution



I tried rearranging this equation to solve for r
 
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Not quite. The idea is that there are two charges, the 40 uC charge is at a particular location, you need to figure out where another one must be placed to make the net field zero at the origin.

How do you find the electric field resulting from two charges?

Conceptually, around where would you guess the other charge should be placed?
 
Well I know it has to be located further to the right.

To find the Electric field from 2 charges... it wouldn't be as simple as using the equation E=Ke(q/r^2)?
 
Bearbull24.5 said:
Well I know it has to be located further to the right.
Totally.

Bearbull24.5 said:
To find the Electric field from 2 charges... it wouldn't be as simple as using the equation E=Ke(q/r^2)?
Not quite. That's the field due to a single point charge. Electric fields obey the principle of 'superposition,' however. To find the net field, you simply add the fields from each individual charge.
Formally:
<br /> E_{net} = \sum_{i=1}^{n} E_i<br />
for n charges
 

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