Which Acid Is Stronger, HA or HB?

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Acid HB, with a pKa of 10, is stronger than acid HA, which has a pKa of 20. When Na+ A- is added to HB, an acid-base reaction is expected to occur, resulting in the formation of B- and HA. This is because HB, being a stronger acid, leads to A- acting as a stronger base. The relationship between pKa and the strength of conjugate bases indicates that a stronger acid corresponds to a weaker conjugate base. Understanding these principles clarifies the dynamics of the acid-base reaction in question.
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Homework Statement


Acid HA has a pKa=20; acid HB has a pKa=10
a. which is the stronger acid?
b. will an acid-base reaction with an equilibrium lying to the right take place if Na+ A- is added to HB? Explain your answer.


Homework Equations





The Attempt at a Solution


I know that the lower pKa is a stronger acid, which makes answer a is HB
I'm not really sure what b is asking. I want to say yes because HB is a strong acid, so adding Na+ A- (weak base) will cause an acid base reaction. I'm like clueless with b. Can someone help and tell me where to start ffor b? thank you in advance..
 
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What it really asks if it this reaction will happen:

HB + A- = B- + HA

and to find the answer you have to know which conjugate base - A- or B- is stronger.

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methods
 
HB + A- = B- + HA

strong acid + A- = B- + weak acid

Since HB is a stronger acid, isn't A- a stronger base? stronger acid=weaker conj. base?
 
so answer is yes
 
Yes it is yes :wink:

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methods
 
thank you so to explain my answer :
HB + Na+ A- = B- + HA

Since HB is a stronger acid, A- is a stronger base, stronger acid=weaker conj. base
 
I'm not sure how knowing how strong a conjugate base will be can help you here if you don't already know which is the stronger acid beforehand. That is circular reasoning IMO.

You should remember that the pKa is the pH at which half of the acid is deprotonated. The higher the pKa, the higher the pH must be to deprotonate it. Thus, the compound with the higher pKa must be the weaker acid since it requires a stronger base to deprotonate it.
 
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