Which compound will be extracted in organic layer?

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SUMMARY

The discussion centers on the extraction of compounds using dichloromethane and sodium hydroxide in a liquid-liquid extraction process. The user initially predicts that compounds (A) and (B) will be extracted into the aqueous layer due to their ability to form charged conjugate bases when deprotonated by NaOH. However, the answers indicate that both (A) and (B) are extracted into the organic layer, while compound (C) remains in the aqueous layer, contradicting the user's reasoning. This highlights the importance of understanding the behavior of acids and bases in organic chemistry extractions.

PREREQUISITES
  • Understanding of liquid-liquid extraction principles
  • Knowledge of acid-base chemistry, specifically deprotonation
  • Familiarity with organic solvents, particularly dichloromethane
  • Basic concepts of charged and neutral species in solution
NEXT STEPS
  • Research the mechanisms of liquid-liquid extraction in organic chemistry
  • Learn about the properties of dichloromethane as a solvent
  • Study the behavior of phenols and carboxylic acids in basic solutions
  • Explore the concept of conjugate bases and their solubility in organic vs. aqueous layers
USEFUL FOR

Chemistry students, organic chemists, and laboratory technicians involved in extraction processes and acid-base reactions.

vetgirl1990
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I'm having a lot of trouble predicting which compounds would be extracted into which layer (organic vs. aqueous) using acids and bases.

Using the solvents dichloromethane (which would form the organic layer) and sodium hydroxide (would form the aqueous layer along with water), I am asked to predict which of the following compounds would end up being extracted into the organic layer.

My predictions for the attached compounds:
(A) Would be extracted in the AQUEOUS layer.
NaOH would deprotonate the hydrogen (on the OH) from the bezoic acid, leaving a charged conjugate base.
Charged materials stay in the aqueous layer.

(B) Would be extracted in the AQUEOUS layer.
NaOH would deprotonate the hydrogen (on the OH) from the phenol, leaving a charged conjugate base.
Charged materials stay in the aqueous layer.

(C) Would be extracted in the ORGANIC layer.
NaOH attacks the NH3+ group, forming a neutral compound, and anionic dicyclohexane.
The neutral compound that forms would be extracted in the organic layer.

BUT my reasoning seems to be all wrong! The answers state that compounds (A) and (B) will be extracted into the organic layer, but (C) would not be. Why?
 

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A)? Check. B)? Check. C)? Check.
This could be a "re-cycled" pre-lab that hasn't been proof-read --- who knows.
 
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Bystander said:
A)? Check. B)? Check. C)? Check.
This could be a "re-cycled" pre-lab that hasn't been proof-read --- who knows.

Interesting, that's what I was thinking too... so is my reasoning above correct then? Regarding the base being able to deprotonate A and B to form a charged conjugate base; and neutralizing C to form a neutral compound?
 
That's my take.
 
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