Which Equation Best Describes the Block's Height After a Bullet Impact?

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Homework Statement


Which equation could adequately be used to determine how high the block goes after being hit by the bullet (a height h)? (see figure) (m+M)gh+ksh=1/2(m+M)V^2
(m+M)gh+1/2ksh^2=1/2(m+M)V^2
(m+M)v+ksh=(m+M)V

Homework Equations


KE=1/2mv^2
Ugrav=Mgh
PE of spring = 1/2ks(s^2 final - s^2 initial)

The Attempt at a Solution



Based off of the equations, I believe the answer should be the second equation. I don't understand what else it could be..

I have only one attempt
 

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Westin said:

Homework Statement


Which equation could adequately be used to determine how high the block goes after being hit by the bullet (a height h)? (see figure)(m+M)gh+ksh=1/2(m+M)V^2
(m+M)gh+1/2ksh^2=1/2(m+M)V^2
(m+M)v+ksh=(m+M)V

Homework Equations


KE=1/2mv^2
Ugrav=Mgh
PE of spring = 1/2ks(s^2 final - s^2 initial)

The Attempt at a Solution



Based off of the equations, I believe the answer should be the second equation. I don't understand what else it could be..

I have only one attempt
Some of the variables in those equations need to be definrd for us.

I see L1, m, v, and h in the figure.

What are k, s, M, V, an s without k ? Is that ks rather than k⋅s ?
 
Maybe you could explain why you think it couldn't be the other two equations you excluded?
 
paisiello2 said:
Maybe you could explain why you think it couldn't be the other two equations you excluded?

Because the other two equations are missing components to their equations
 
SammyS said:
Some of the variables in those equations need to be definrd for us.

I see L1, m, v, and h in the figure.

What are k, s, M, V, an s without k ? Is that ks rather than k⋅s ?

1/2ks(s^2 final - s^2 initial)

ks = spring constant (k_s_)
(s^2 final - s^2 initial) = final stretch - initial stretch
v= velocity
m=mass1
M=mass2
 
Westin said:
Because the other two equations are missing components to their equations
And what components do these two equations have that are missing that the other one isn't?
 
paisiello2 said:
And what components do these two equations have that are missing that the other one isn't?
(m+M)gh+ksh=1/2(m+M)V^2 the spring constant should be 1/2ksh^2 not ksh
(m+M)gh+1/2ksh^2=1/2(m+M)V^2
(m+M)v+ksh=(m+M)V Ugrav should be (m+M)gh instead of velocity multiplying the masses (m+M)v, also (m+M)V is missing V^2
 
I think you have your answer then.