Which Graph Best Represents the Stone's Angular Momentum Over Time?

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SUMMARY

The discussion focuses on determining the correct graph representing the angular momentum (L) of a stone falling from rest, as a function of time. The key conclusion is that the angular momentum is linear in time, represented by the equation L = c * t, where c is a constant. The participants utilized the definition of angular momentum as the cross product of position (r) and momentum (p), leading to the understanding that the only variable changing with time is the linear momentum. The discussion also highlights the importance of recognizing the horizontal distance from the point of rotation to the stone's path as a constant factor in the calculations.

PREREQUISITES
  • Understanding of angular momentum and its mathematical definition
  • Familiarity with cross product operations in vector mathematics
  • Basic principles of kinematics, particularly free fall
  • Knowledge of AP Physics C curriculum and problem-solving strategies
NEXT STEPS
  • Study the concept of angular momentum in detail, focusing on its derivation and applications
  • Learn about the cross product and its geometric interpretation in physics
  • Explore kinematic equations related to free-falling objects and their implications on angular momentum
  • Review sample AP Physics C problems to enhance problem-solving skills in angular momentum scenarios
USEFUL FOR

Students preparing for AP Physics C, physics educators, and anyone interested in understanding the dynamics of angular momentum in falling objects.

awvvu
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Homework Statement


A stone falls from rest from the top of a building. Which of the following graphs' shapes best represents the stone's angular momentum L about the point P as a function of time?

http://img413.imageshack.us/img413/1033/54161793ev0.png

a) L = 0
b) L = c (constant)
c) L = c * t (linear in t)
d) L = t^2
e) L = upside-down parabola with vertex at some positive x and positive y, passing through the origin

The Attempt at a Solution


I think I solved this problem using the definition of angular momentum as the cross product of r and p (calling point P (x_0, y_0)):

\vec{L} = \vec{r} \times \vec{p} = \left| \begin{array}{ccc}<br /> \hat{i} &amp; \hat{j} &amp; \hat{k} \\<br /> r_x &amp; r_y &amp; 0 \\<br /> 0 &amp; p_y &amp; 0 \end{array} \right| = r_x p_y \hat{k} = x_0 m g t \hat{k}

where r_x = x_0 and p_y = - m g t

So apparently linear momentum is linear in time. This question is for an AP Physics C sample multiple choice, so I have a hard time believing they want us to evaluate a cross-product to figure out this. Is there some intuitive way to understand this? Or a quick way to do it? I tried using the definition of cross product as r p \sin(\theta) but that doesn't get me very far either.
 
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Hi awvvu,

About your definition rp \sin(\theta), I think that is a good way to see it. If you think about the path of the stone as it falls (vertically), notice that r and theta both change with time, but r\sin\theta is a constant--it's just the horizontal distance from the point to the ball's path. So the only thing changing with time in rp \sin(\theta), is p.

There are also the slightly differently-written forms m v_{\perp} r and m v r_{\perp} for the angular momentum of a particle. The second form works best here: you know the velocity is vertical, so r_{\perp} must be the horizontal distance.
 
Ah, I was trying to look at each multiplied term separately and I couldn't figure out the relationship between r and sin(theta).
 

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