SUMMARY
The integral \(\int_{0}^{\pi} e^{\sin^2 x}\,dx\) is definitively larger than \(\frac{3\pi}{2}\). This conclusion is reached by applying the inequality \(e^x > 1+x\) for \(x = \sin^2 x\), which holds true for all \(x\) except \(x=0\). The evaluation shows that \(\int_{0}^{\pi} e^{\sin^2 x}\,dx\) exceeds the integral \(\int_0^\pi (1 + \sin^2x)\,dx\), which equals \(\frac{3\pi}{2}\). Therefore, the integral of the exponential function with the sine squared argument is greater than the specified constant.
PREREQUISITES
- Understanding of definite integrals
- Familiarity with the properties of exponential functions
- Knowledge of the sine function and its square
- Basic skills in mathematical inequalities
NEXT STEPS
- Study the properties of the exponential function, particularly \(e^x\)
- Learn about the application of inequalities in calculus
- Explore advanced techniques in evaluating definite integrals
- Investigate the behavior of integrals involving trigonometric functions
USEFUL FOR
Mathematicians, calculus students, and anyone interested in integral calculus and inequalities will benefit from this discussion.