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Turion
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Are they both correct? Would the first or second solution be preferred?
phyzguy said:The second one is certainly not a solution. There is a solution in terms of exponentials, but that is not it.
Turion said:Why is the second one not a solution? If you convert the original DE into an auxiliary equation, you will get roots: m1=0 and m2=k2
phyzguy said:No you don't. You get roots of +k and -k. Try plugging your second solution into the DE and see if it works. You'll see that it doesn't.
Exact solutions for a differential equation are those that satisfy the equation exactly, while approximate solutions are those that are close enough to the actual solution but may not satisfy it exactly.
The best approach for solving a differential equation depends on its type and complexity. Generally, it is best to start with simpler methods such as separation of variables and then move on to more advanced methods if necessary.
While numerical methods can provide accurate solutions to differential equations, they can also be time-consuming and computationally expensive. It is important to consider the trade-off between accuracy and efficiency when choosing a solution method.
Yes, there are many software programs and packages available that can solve differential equations for you. However, it is important to have a basic understanding of the different solution methods and their limitations in order to interpret the results correctly.
Not necessarily. The "best" solution will depend on the specific circumstances and constraints of the problem. It is important to consider factors such as accuracy, efficiency, and interpretability when choosing a solution method.