- #1
Turion
- 143
- 2
Are they both correct? Would the first or second solution be preferred?
The second one is certainly not a solution. There is a solution in terms of exponentials, but that is not it.
Are they both correct? Would the first or second solution be preferred?
Why is the second one not a solution? If you convert the original DE into an auxiliary equation, you will get roots: m_{1}=0 and m_{2}=k^{2}
No you don't. You get roots of +k and -k. Try plugging your second solution into the DE and see if it works. You'll see that it doesn't.