- #1
BiGyElLoWhAt
Gold Member
- 1,637
- 138
Hmmm maybe this goes here, maybe it doesn't.
https://en.wikipedia.org/wiki/Ionocraft
Here is a picture that depicts basically what I'm talking about.
From what I understand, Ionocrafts work on N3L, and shoot ions down, pushing the craft up. This makes me think that the more charges you have, the more thrust you can get. This makes me think you want lots of charges and low weight. (stop me when I mess up)
This makes me think for the shape of the base, you would want a high cross-sectional area to perimeter ratio. I keep seeing things about equilateral triangles being used.
Why?
##\frac{\text{area}}{\text{perimeter}}##
Circle:
##\frac{\pi r^2}{2 \pi r} =\frac{r}{2}##
Square (half the length of a side is r):
##\frac{(2r)^2}{4(2r)} =\frac{r}{2}##
equilateral triangle (height is r, b is 1/2 side):
##\frac{2*1/2*b*r}{3*2*b} = \frac{r\frac{r}{\sqrt{3}}}{3*\frac{2r}{\sqrt{3}}} = \frac{r}{6}##
So, hold the distance from the wire on top to the plane constant, and approximate the field inside the ionocraft as constant (or at least the vertical component, the outwards components will cancel because symmetry). You have equal charges/unit mass (or per unit length) in a circle and square. However, you have 1/3 as many charges with the equilateral triangle (per unit length of material i.e. per unit mass), and thus 1/3 the force (##F_{thrust} = -\Sum q E##)
What's the draw to the equilateral triangle?
Perhaps it's just an artifact of my inconsistent definition of r? But it's ratios, and I just used r as a means to calculate and compare, hmm...
https://en.wikipedia.org/wiki/Ionocraft
Here is a picture that depicts basically what I'm talking about.
From what I understand, Ionocrafts work on N3L, and shoot ions down, pushing the craft up. This makes me think that the more charges you have, the more thrust you can get. This makes me think you want lots of charges and low weight. (stop me when I mess up)
This makes me think for the shape of the base, you would want a high cross-sectional area to perimeter ratio. I keep seeing things about equilateral triangles being used.
Why?
##\frac{\text{area}}{\text{perimeter}}##
Circle:
##\frac{\pi r^2}{2 \pi r} =\frac{r}{2}##
Square (half the length of a side is r):
##\frac{(2r)^2}{4(2r)} =\frac{r}{2}##
equilateral triangle (height is r, b is 1/2 side):
##\frac{2*1/2*b*r}{3*2*b} = \frac{r\frac{r}{\sqrt{3}}}{3*\frac{2r}{\sqrt{3}}} = \frac{r}{6}##
So, hold the distance from the wire on top to the plane constant, and approximate the field inside the ionocraft as constant (or at least the vertical component, the outwards components will cancel because symmetry). You have equal charges/unit mass (or per unit length) in a circle and square. However, you have 1/3 as many charges with the equilateral triangle (per unit length of material i.e. per unit mass), and thus 1/3 the force (##F_{thrust} = -\Sum q E##)
What's the draw to the equilateral triangle?
Perhaps it's just an artifact of my inconsistent definition of r? But it's ratios, and I just used r as a means to calculate and compare, hmm...