Why are the calculated energies for two oscillating waves not equal?

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SUMMARY

The discussion centers on the calculation of energy for two oscillating waves affecting a water atom and the conditions for minimizing light loss in a thin film of glass. The equations presented for the energies of the two waves, E1 = (1/2)m.(w^2)(A1^2) and E2 = (1/2)m.(w^2)(A2^2), lead to a total mechanical energy of (1/2)m.(w^2)(A1^2 + A2^2). However, the derived total displacement A does not satisfy the condition A^2 = A1^2 + A2^2, indicating a misunderstanding in the superposition principle. Additionally, the discussion confirms that for optimal light transmission through a thin film, reflected light waves must indeed interfere destructively to minimize reflection losses.

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thuanthuan
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Hi everyone,
I have a question about waves.

Suppose there are two waves that make one water atom vibrate.
The first equation of oscillation is: x1= A1sin(wt+p1), energy propagated to the atom is (1/2)m.(w^2)(A1^2)
and the other: x2=A2sin(wt+p2), E2 = (1/2)m.(w^2)(A2^2)
so the total energy (mechanical) of the atom is (1/2)m.(w^2)(A1^2+A2^2)

On the other hand, the total displacement is x=x1+x2=A(sinwt+p), where A=A1^2+A2^2-2A1A2cos(p1-p2)
so the energy = (1/2)m.(w^2)(A^2)

but A^2 doesn't equal to A1^2+A2^2

so the two energy calculated are not equal

what's wrong with my calculation ?

Thank you.
 
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A similar question, Suppose we have a thin film of glass with an index of diffraction is n
The upper and lower surfaces of the flim is parellel. Light is incident to the flim.

So a portion of light is reflected at the upper surface, the rest is refracted into glass. Light continues to the lower surface, then one portion of it is refracted back into air, one portion is reflected.

Someone say that to minimize the light loss due to reflection (that is, the final light traveling back to the air is maximized), then two reflected line must destructively interfere with each other. Is that true ? Can you explain why ?
 

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