Why can we add/subtract constants to potential function?

Click For Summary
SUMMARY

The discussion clarifies that adding or subtracting a constant to a potential energy function, such as V(x), is permissible due to the invariance of quantum mechanics (QM) and classical physics equations under changes in the zero of energy. This practice is primarily for convenience, as it does not affect measurable forces, which are derived from the spatial derivative of the potential. For example, in the harmonic oscillator, the potential minimum is set to zero, while in the hydrogen atom, the zero corresponds to infinitely separated proton and electron, resulting in a ground state of -13.6 eV.

PREREQUISITES
  • Understanding of quantum mechanics (QM) principles
  • Familiarity with classical physics concepts
  • Knowledge of potential energy functions
  • Basic calculus, particularly derivatives
NEXT STEPS
  • Explore the implications of energy zero-point shifts in quantum mechanics
  • Study the harmonic oscillator model in detail
  • Investigate the Coulomb potential and its applications in atomic physics
  • Learn about the relationship between force and potential energy in classical mechanics
USEFUL FOR

Students and professionals in physics, particularly those studying quantum mechanics and classical mechanics, as well as anyone interested in the mathematical treatment of potential energy functions.

MrApex
Messages
21
Reaction score
0
I have 3 questions regarding the topic:
1-Why is that we are allowed to add or subtract a constant to a potential energy function V(x) to set it to zero where it is constant?
2-What does adding/subtracting a constant physically correspond to if anything at all?
3- Do we do it simply for convenience ?

Thanks in advance
 
Physics news on Phys.org
The equations of QM (and for that matter, classical physics also) are invariant under a change of the zero of energy. All calculations will give the same result, whatever your choice of origin for energy. Therefore, it is only a matter of convenience where to set it.

For the harmonic oscillator, one usually takes the minimum of the potential to be at zero, while for the Coulomb potential in the hydrogen atom, one usually takes the zero to correspond to infinitely separated proton and electron, such that the ground state is at -13.6 eV.
 
  • Like
Likes   Reactions: MrApex
One way to think about this is that potential energy isn't something that is directly measurable. But force is something that we can measure directly. The potential is defined as the negative spatial derivative of the force. The derivative of a constant term is zero. It follows that we can add a constant term to the potential without changing our characterization of the force. "Physically", adding or subtracting a constant corresponds to nothing at all, since it has no effect on the "physically apprehensible" force. We just pick our zero for convenience and convention.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
11K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
29
Views
3K
  • · Replies 31 ·
2
Replies
31
Views
4K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K