Why Capacitors Store Half The Charge They Are Given

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Homework Help Overview

The discussion revolves around the behavior of capacitors, specifically addressing the equations related to charge storage and energy. Participants are exploring the relationship between charge, capacitance, and voltage, as well as the implications of these equations in understanding how capacitors function.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are questioning the interpretation of the equations Q=CV and Q=0.5CV, particularly the meaning of the latter in terms of charge storage. There is curiosity about the fate of the charge not stored and the reasoning behind the half-charge concept. Some participants suggest that the focus should be on energy rather than charge.

Discussion Status

The discussion is active, with participants providing clarifications on the equations and their implications. There is an ongoing exploration of terminology and concepts, particularly regarding the distinction between charge and energy. Multiple interpretations of the equations are being considered without a clear consensus yet.

Contextual Notes

Participants are navigating potential misunderstandings about the relationships between charge, voltage, and energy in capacitors. There is an emphasis on ensuring correct terminology and understanding of the underlying physics principles.

Dark Red Rose
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I have been studying capacitors this week and learned two equations. One is Q=CV and the other is Q=0.5CV. The latter equation is derived from C-V graph. From this it shows that half the charge delivered is stored. I am very curious to know where the other half of the charge go and why is the charge stored exactly half of the charge supplied? How is the half of the charge which is not stored used?
 
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Dark Red Rose said:
I have been studying capacitors this week and learned two equations. One is Q=CV and the other is Q=0.5CV. The latter equation is derived from C-V graph. From this it shows that half the charge delivered is stored. I am very curious to know where the other half of the charge go and why is the charge stored exactly half of the charge supplied? How is the half of the charge which is not stored used?
The charge stored in a capacitor of capacitance, C, with a potential difference, V, across its plates is Q = CV .

The energy stored in such a capacitor is (1/2)CV2. That doesn't mean that the charge is (1/2)CV.
 
Dark Red Rose said:
From this it shows that half the charge delivered is stored. I am very curious to know where the other half of the charge go and why is the charge stored exactly half of the charge supplied? How is the half of the charge which is not stored used?

Replace the word 'charge' in this paragraph with the word 'energy' and you will then have a good question. As Sammy was implying, all of the charge delivered is stored.

P.S. you have an awesome name. and welcome to physics forums!
 
You have your terms mixed up
C = Q/V or Q = C x V or V = Q/C...these give the relationships between Q, C and V.
The graph I think you are talking about is Q against V (not C ~ V)
This graph enables you to calculate the ENERGY stored on the capacitor, the ENERGY equations are
E 0.5QV...or 0.5CV^2 or 0.5Q^2/C
 

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