Why do electrons form a 'sea' in metallic bonding?

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Electrons dissociate from metal atoms due to their relatively low binding energy, allowing them to move freely within the metallic structure. This movement creates a 'sea' of electrons that surrounds positively charged metal ions. The balance between the number of electrons and the positive charges from the ions results in no net repulsion between the ions. Additionally, the proximity of the electrons to the ions creates a net attractive force, contributing to the overall strength of metals. This explains the unique properties of metallic bonding and the stability of metallic structures.
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My lecturer writes the following in his lecture notes:
“ In metals electrons dissociate from atoms and form a ‘sea’ of electrons which reduces the repulsion between the metal ions.”

Why do electrons dissociate from atoms in metals?

How does a sea of electrons reduce the repulsion between the metal ions?
 
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hasan_researc said:
1. Why do electrons dissociate from atoms in metals?

2. How does a sea of electrons reduce the repulsion between the metal ions?

1. It's all about the relative binding energy. The energy which binds an outer electron to a metal atom is not any higher than what binds it to the nearby atoms - so the electron can move freely from place to place - as opposed to what often goes on with a non metal or when the adjacent atoms happen not to be metals.

2. The number electrons in the 'sea' is the same as the number of 'extra' protons in all the ion 'cores'. This gives a balance in total charges. Each ion is surrounded by just the same number of + and - charges so no net repulsion. In fact, of course, the nearest electrons are closer than the nearest +ions so there is net attraction (hence the strength of metals).
 
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