Why do LEDs continue to emit light?

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SUMMARY

LEDs continue to emit light due to the recombination of electrons and holes within the semiconductor material. When a voltage is applied, electrons gain sufficient energy to cross the potential barrier between N-type and P-type semiconductors, allowing them to recombine with holes and emit light at specific wavelengths. The density of holes decreases as they are filled, but holes are continuously created and destroyed, maintaining a dynamic equilibrium that allows for ongoing light emission. This process is influenced by the diffusion of holes from areas of high density to low density, ensuring a consistent supply for recombination.

PREREQUISITES
  • Understanding of semiconductor physics, specifically P-type and N-type materials
  • Knowledge of electron-hole recombination processes
  • Familiarity with voltage application in semiconductor devices
  • Basic principles of electric fields and charge density
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  • Research the principles of electron-hole recombination in semiconductors
  • Study the effects of voltage on P-N junctions in LED technology
  • Learn about the diffusion process of charge carriers in semiconductors
  • Explore the impact of electric fields on hole mobility and density
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Electrical engineers, physicists, and anyone interested in the operational principles of LEDs and semiconductor technology.

jaydnul
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The electrons need energy to cross the potential barrier between the N and P types. So apply a voltage and they get over and recombine with the "holes" and emit a certain wavelength of light. Then what happens? Does the voltage have to be great enough to then knock them out of the holes and send them down the conducting wire so a new electron can fill the same hole? How do they continue to emit light after all the holes are initially filled?
 
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Jd0g33 said:
The electrons need energy to cross the potential barrier between the N and P types. So apply a voltage and they get over and recombine with the "holes" and emit a certain wavelength of light. Then what happens?
Density of holes decreased at that point where the hole disappeared. Random motion of holes tends to keep the density of holes homogeneous. So eventually some hole will drift to that position.

Holes are constantly being destroyed at one end of the p-type semiconductor, while at the other end holes are being created. The holes diffuse from high hole density area to low hole density area.

To get electric fields mentioned, I add that a hole reacts to density of holes and other charges at a distance, in other words hole reacts to electric fields.
 

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