Why do we need to renormalize in QFT, really?

In summary: Basically, it amounts to constructing a multiplication algebra for distributions which allows for order by order multiplication.
  • #1
jakob1111
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There are several reasons given in the literature, why UV infinities arise in QFT in the first place. My problem is putting them together, i.e. understand how they are related to each other.

So... UV divergences arise and thus we need to renormalize, because:

  1. We have infinite number of degrees of freedom ín a field theory. (From this perspective, the infinites seem inevitable.)
  2. We multiply fields to describe interactions, fields are distributions and the product of distributions is ill-defined.
  3. We neglect the detailed short-wavelength structure of scattering processes, and the infinites are a result of our approximations with delta potentials. (From this point of view, the UV divergences aren't something fundamental, but merely a result of our approximation method. )
  4. We are dealing with non-self-adjoint Hamiltonians. (This is closely related to the 3. bullet point. From this perspective an alternative to the "awkward" renormalization procedure would be the "method of self-adjoint extension".)
Are these reasons different sides of the same coin? And if yes, how can we understand the connection between them?
 
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  • #2
0. Noninteracting field theories are an incredibly bad starting point to describe interacting field theories.
 
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  • #3
DrDu said:
0. Noninteracting field theories are an incredibly bad starting point to describe interacting field theories.

In most of the cases the possible interacting field theories are mathematically derivable from the free/noninteracting ones.
 
  • #4
dextercioby said:
In most of the cases the possible interacting field theories are mathematically derivable from the free/noninteracting ones.
I don't know of any realistic interacting field theory which is derivable from free ones.
 
  • #5
DrDu said:
I don't know of any realistic interacting field theory which is derivable from free ones.

The self-interactions in QCD (Yang-Mills fields) are derivable from the free theory of electromagnetism (in fancy mathematics language: the only physically relevant deformation of the U(1) gauge algebra is a compact Lie algebra).
 
  • #6
2. and 4. are closely related.

Quantum fields are operator valued distributions. Like all distributions there is no natural notion of multiplication for them. By "natural" I mean there are several ways of defining how one should multiply two distributions (the only thing they have in common is that when restricted to functions they agree with the normal notion of multiplying functions). The Colombeau algebra is one example of a multiplication algebra for distributions.

The naive way of multiplying functions, pointwise multiplication, results in nonsense for distributions. This is the mathematical origin of infinities in QFT.

For QFTs it turns out that the correct notion of multiplication is intimately tied to the operator component. One can only correctly define the multiplication of the fields on a specific Hilbert Space. On that Hilbert Space, the correct multiplication will amount to normal ordering. Once that normal ordering is performed the Hamiltonian automatically becomes self-adjoint.

In this, mathematically rigorous, view renormalization is essentially the process of slowly constructing the inner-product which defines the correct Hilbert Space and normal ordering the fields (order by order in the coupling constant).

Short Version:
Renormalization occurs because QFTs live in different Hilbert Spaces. On the wrong Hilbert Space the field multiplications occurring in the Hamiltonian are nonsensical and ill-defined. Only on the correct Hilbert Space is the Hamiltonian self-adjoint after normal ordering. Unfortunately the correct Hilbert Space is different for each Hamiltonian.

So:
local fields = operator valued distributions = problem above.

1. is simply a consequence of using local fields. Although one can have infinite degrees of freedom without running into the problem above.

3. is just an idea for how one might replace local fields, but I don't think its the reason for renormalization.
 
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1. Why is renormalization necessary in quantum field theory (QFT)?

Renormalization is necessary in QFT because it allows us to remove infinities that arise in calculations of physical quantities, such as particle masses and interactions. These infinities arise due to the self-interactions of particles in the field, and without renormalization, the theory would not be able to make accurate predictions.

2. What exactly is renormalization in QFT?

Renormalization in QFT is a mathematical technique used to remove infinities in calculations of physical quantities. It involves modifying the parameters of the theory, such as particle masses and coupling constants, to account for the effects of these infinities. This allows the theory to make predictions that are both finite and physically meaningful.

3. How does renormalization work in QFT?

Renormalization in QFT involves a process of rescaling or redefining the parameters of the theory to account for the effects of infinities. This is typically done by subtracting the infinite contributions from the physical quantities and replacing them with finite, renormalized values. The resulting theory can then be used to make accurate predictions about the behavior of particles and their interactions.

4. Is renormalization a fundamental concept in QFT?

Yes, renormalization is a fundamental concept in QFT. It is an essential part of the theory and is used to make predictions that agree with experimental results. Without renormalization, the theory would not be able to account for the effects of self-interactions and would not be able to make accurate predictions about physical quantities.

5. Are there any limitations to renormalization in QFT?

While renormalization is a powerful and essential tool in QFT, it does have some limitations. One of the main limitations is that it only works for theories that are renormalizable, meaning that the infinities can be removed by a finite number of renormalization procedures. In some cases, non-renormalizable theories may require other techniques to account for infinities, such as regularization.

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