Science Advisor
Homework Helper
- 30,594
- 7,548
And that is. . . ?
I used the ball motion from the video. See post #112 & #114.sophiecentaur said:Does 'your' theory account for the ball motion being in the direction that the cue points
From what I have seen so far in this specific case, it seems not very relevant for the initial horizontal motion of the ball, right after the hit.sophiecentaur said:Do you claim that contact with the table is not relevant?
Have you observed that the motion appears to be in the line of the cue? Are you aware that there is a extra, lateral force involved (Described by players) which would produce a lateral motion. How are those two things reconciled if simple (2 D) theory tells us the ball travels in the direction of the force? There has to be another force involved. Can you think of a better mechanism than contact with the table?A.T. said:I used the ball motion from the video. See post #112 & #114.From what I have seen so far in this specific case, it seems not very relevant for the initial horizontal motion of the ball, right after the hit.
sophiecentaur said:Something that you could help me with would be to explain when and why the "English" shot is choses, over a straight impact. Something to do with bending the path of the ball, I guess. Those professionals do some annoyingly clever stuff with how the ball behaves.
sophiecentaur said:Have you observed that the motion appears to be in the line of the cue? Are you aware that there is a extra, lateral force involved (Described by players) which would produce a lateral motion. How are those two things reconciled if simple (2 D) theory tells us the ball travels in the direction of the force? There has to be another force involved. Can you think of a better mechanism than contact with the table?
Yes. It's definitely more complex than a simple 2D problem. Your comment on vertical cue angle is interesting. It would control slip and encourage the steering action. It's all very non linear so limiting friction is probably very relevant at all points of contact.David VH said:As an aside, as far as I know there are two distinct reasons to play with side (English). First is to swerve the cueball around an obstacle. The motion has two phases, first it goes fairly straight as it slips over the table, then it slows down and as it starts rolling, the side "takes" and the ball curves into the direction of the side. It's an easy way to get out of a snooker. The second common shot with side is to affect cueball position after it hits the object ball. The collision slows the cueball, the side takes from the collision onwards and the cueball rolls off into a direction different from the collision tangent.
I think your reasoning is sound. I only read 4 pages of this thread and skimmed over the rest (sorry) but it seems one factor has not been discussed in any detail, and that is that the cueball bounces off the table. It is nearly impossible to play a shot with a horizontal cue, so the friction contact between cue and cueball is pushing the cueball into the cloth. As the cue releases the cueball, the cueball bounces up off the cushion. Depending on the shot this is more or less pronounced, but in my experience (and backed up by your reasoning about the origin of lateral force) it always happens to some extent.
What I'm trying to say is, because of the downward angle of the cue, you are always pushing the ball into the cloth, so the spin axis of the ball is tilted forwards even on a vertically neutral (no top or back spin) shot.
As I have been saying throughout the thread. But for the specific case with the ball spinning around a close to vertical axis, a simple 2D approach seems to explain the result quite well.sophiecentaur said:It's definitely more complex than a simple 2D problem.
A.T. said:As I have been saying throughout the thread. But for the specific case with the ball spinning around a close to vertical axis, a simple 2D approach seems to explain the result quite well.
A.T. said:Maybe you can draw a diagram to explain better what you mean here. It's to vague.
poolplayer said:
Yes, I also made this point earlier in the thread. But how relevant is this effect really, during the short impact phase, if you strike as horizontal as possible, at mid height?David VH said:What I'm trying to say is, because of the downward angle of the cue, you are always pushing the ball into the cloth, so the spin axis of the ball is tilted forwards even on a vertically neutral (no top or back spin) shot.
A complicating factor here is that a flexing cue will extend the contact time and a different amount of slip across the surface of the ball, which will (could) mean that there is more imparted spin round a vertical axis.rcgldr said:As noted many times by now, there are lateral component forces (Newton third law pair) between the cue tip and the cue ball, but since the cue stick flexes to the right, the cue tip has more of a reaction to the lateral component forces than the cue ball, so that the cue ball isn't deflected to the left much by the impact.
Is the cue ever horizontal? I watch a fair amount of Snooker on TV and the close up shots suggest there is nearly a significant downwards tilt when a hand bridge is used, True, the X rest is a bit lower than the hand but isn't the cue axis still higher than the centre of the ball? That downwards angle helps to strike with the flat end of the cue tip and will help to avoid unwanted slip against the table. The 1/10 factor you quote would be easily enough to control slip and a steeper attack would cause bounce and make control harder. Unsurprisingly, the angle has been chosen to work optimally.A.T. said:Yes, I also made this point earlier in the thread. But how relevant is this effect really, during the short impact phase, if you strike as horizontal as possible, at mid height?
sophiecentaur said:The 1/10 factor you quote would be easily enough to control slip...
That seems the wrong way round to me. The limiting friction force is less than the normal force but the normal component of the cue's force will increase the normal force (usually just the weight) considerably. 1/10 of the net, brief force from the cue will be greater (or at least as great) than the weight of the ball, which is easy to show from the fact that a struck ball can be lifted to a significant height above the table in some trick shots. So the net friction force, which is what will cause the ball to rotate, will be significantly higher with a slightly downwards stroke. It will be approximately proportional to the angle, aamof, because sin and tan are about the same as the angle for small angles (radians of course). Even if there is slippage, the tangential force against the table will still be greater than with a horizontal impact.A.T. said:The 1/10 factor is for the table normal force. The max. table friction is just a fraction of that (~0.2). And the lateral friction component is some fraction of that. This limits the lateral table friction to ~0.02 of the horizontal cue impact force (in the specific case I was considering).
Higher than from gravity alone. But still just ~2% of the horizontal force from a 5° downwards stroke. So at most ~1° horizontal direction change.sophiecentaur said:So the net friction force, ..., will be significantly higher with a slightly downwards stroke.
A.T. said:Higher than from gravity alone. But still just ~2% of the horizontal force from a 5° downwards stroke. So at most ~1° horizontal direction change.
If the friction is 0.02 of the impact force, then it can change the direction of the net force by max. atan(0.02) ~= 1°. But that assumes that it acts perpendicularly to the impact force, so it's actually even less than 1°.David VH said:How did you come to the 1 degree (could be correct, I don't see all the relevant math in my head)?
Not for the question of the OP, which is to explain the ~15° deviation from the contact normal in his video.David VH said:1 degree is enormous for a snooker player by the way.
A.T. said:Not for the question of the OP, which is to explain the ~15° deviation from the contact normal in his video.
I thought the point of the top of this thread was that the ball goes more or less along the line of the cue and that needed explanation. No one would be surprised if it went as far as 15° off. The videos seem to show very nearly a parallel course and that's what I've been working to. No wonder you (A.T.) and I have been arguing the toss so much.A.T. said:If you agree that cue friction explains most of the ~15°, and table friction accounts for merely ~1° at best, then we have no disagreement.
In the video I am referring to (Post #24) the ball path is parallel with the cue. That was what the question needed an explanation for, as far as I can see. Have you seen it?A.T. said:It goes ~15° off the contact normal. That was what the OP asked about.
Exactly. I don't think the cue ball goes dead parallel with the cue, and I don't care 1° difference for now.A.T. said:It goes ~15° off the contact normal. That was what the OP asked about.
How can you be sure that? You really push the friction between the ball and table... The cue angle would be always downwards in the game because there are rails, but we always try to strike horizontally as possible. So, the angle should be less than 5° in most cases. In my videos, I would say shots are very horizontal because there is no rail on my table.sophiecentaur said:Even if there is slippage, the tangential force against the table will still be greater than with a horizontal impact.