Why Does Changing Magnetic Field Direction Affect Current in a Wire Loop?

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SUMMARY

The discussion centers on calculating the induced current in a wire loop when the magnetic field direction changes. A wire loop with an area of 0.32 m² is subjected to a magnetic field that changes from 0.75 T to 0.35 T in the opposite direction over 0.45 seconds. The initial calculation for the electromotive force (emf) was incorrectly computed as 0.284 V, leading to a current of 0.019 A through a 15-ohm resistor. The correct induced current is 0.052 A, indicating a miscalculation in the change of the magnetic field.

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  • Understanding of Faraday's Law of Electromagnetic Induction
  • Knowledge of calculating electromotive force (emf)
  • Familiarity with Ohm's Law (V = IR)
  • Basic concepts of magnetic fields and their units (Tesla)
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  • Learn how to calculate magnetic flux and its changes
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Homework Statement


A loop of wire of aream 0.32m^2 is palced in a 0.75 T magnetic field. The magnetic field is changed to 0.35 T in the opposite direction in 0.45 s . What is the magnitude of the current through the 15 ohm resistor.


Homework Equations


emf = -N (flux / time)


The Attempt at a Solution



emf = (-1) [(.35T)(.32m^2)-(.75T)(.32m^2)]/(.45s)
emf = .284 V
V = IR
I = .284 V / 15ohm
I = .019 A

.019 is the wrong answer in the multiple choice
the correct answer is supposed to be 0.052 A

Thanks
 
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Destrio said:

Homework Statement


A loop of wire of aream 0.32m^2 is palced in a 0.75 T magnetic field. The magnetic field is changed to 0.35 T in the opposite direction in 0.45 s . What is the magnitude of the current through the 15 ohm resistor.


Homework Equations


emf = -N (flux / time)


The Attempt at a Solution



emf = (-1) [(.35T)(.32m^2)-(.75T)(.32m^2)]/(.45s)
emf = .284 V
V = IR
I = .284 V / 15ohm
I = .019 A

.019 is the wrong answer in the multiple choice
the correct answer is supposed to be 0.052 A

Thanks

Looks like you have not computed the change in field correctly.
 

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