Why does (e^{j ω})^{-2} equal e^{-2ω} not e^{-2j ω}?

tempneff · 2014-12-09T03:02:13+00:00

I'm told that (e^{j \omega})^{-2} = e^{-2\omega}...? I thought by the property (a^b)^c=a^{bc} it should equal e^{-2j\omega} What am I missing?

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Start date Dec 8, 2014
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tempneff

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Dec 8, 2014

I'm told that [itex](e^{j \omega})^{-2} = e^{-2\omega}[/itex]...?
I thought by the property [itex](a^b)^c=a^{bc}[/itex] it should equal [itex]e^{-2j\omega}[/itex]
What am I missing?

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Why does (e^{j ω})^{-2} equal e^{-2ω} not e^{-2j ω}?

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Why does (e^{j ω})^{-2} equal e^{-2ω} not e^{-2j ω}?

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