Why does Fresnel's law only use 2 boundary conditions compared to Maxwell's 4?

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Discussion Overview

The discussion centers on the relationship between Fresnel's laws and Maxwell's equations, specifically why Fresnel's laws utilize only two boundary conditions compared to the four provided by Maxwell's equations. Participants explore the implications of this difference and seek intuitive explanations for the redundancy in boundary conditions.

Discussion Character

  • Technical explanation, Conceptual clarification, Debate/contested

Main Points Raised

  • One participant notes that for each polarization, one of Maxwell's equations does not apply, and one equation is equivalent to another, suggesting a simplification in the context of Fresnel's laws.
  • Another participant requests more detailed information on the topic, indicating a desire for deeper understanding.
  • A suggestion is made to consult an intermediate electromagnetic textbook for further clarification on the boundary conditions and their equivalences.

Areas of Agreement / Disagreement

The discussion does not reach a consensus, as participants express varying levels of understanding and seek additional information without resolving the initial question about boundary conditions.

Contextual Notes

Participants do not fully explore the specific boundary conditions or their equivalences, leaving some assumptions and definitions unaddressed.

yavuznuri
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We use only 2 boundary conditions in driving Fresnel's laws, whereas Maxwell's equations provided 4 conditions (2 were identical to other 2). What is the intuitive explanation for this redundancy? which boundary conditions turned out to be equivanlent to each other.
 
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For each polarization, one Maxwell equation doesn't enter, and one equation is equivalent to another. Just write the equatons and you will see this.
 
dear friend, i thank you a lot..but would you please give me detailed information..

sincerely
 
I think you should look at an intermediate EM textbook.
 

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