Why does Fresnel's law only use 2 boundary conditions compared to Maxwell's 4?

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yavuznuri
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We use only 2 boundary conditions in driving Fresnel's laws, whereas Maxwell's equations provided 4 conditions (2 were identical to other 2). What is the intuitive explanation for this redundancy? which boundary conditions turned out to be equivanlent to each other.
 
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For each polarization, one Maxwell equation doesn't enter, and one equation is equivalent to another. Just write the equatons and you will see this.
 
dear friend, i thank you a lot..but would you please give me detailed information..

sincerely
 
I think you should look at an intermediate EM textbook.