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rytmenpinne
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..fullwave bridge rectification raise the voltage *1.41? I scanned the net but I can't find an explanation as to why, only that it does..
Why Does Fullwave Bridge Rectification Raise Voltage by 1.41?
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Discussion Overview
The discussion centers around the phenomenon of fullwave bridge rectification and its effect on voltage, specifically why it raises the voltage by a factor of approximately 1.41. The scope includes conceptual understanding of AC voltage, RMS values, and transformer ratings.
Discussion Character
- Conceptual clarification
- Technical explanation
Main Points Raised
- One participant questions why fullwave bridge rectification raises voltage by 1.41, noting a lack of clear explanations found online.
- Another participant explains that AC voltage is typically expressed in RMS values, relating this to the equation \(\sqrt{2}V_{rms}=V_p\), where \(\sqrt{2}\) is approximately 1.41.
- A participant seeks clarification on whether transformer secondary ratings are given in RMS rather than peak values.
- A later reply confirms that transformer secondary ratings are indeed given in RMS and adds that a bridge rectifier will result in a voltage drop of approximately 1.4 volts due to the current passing through two diodes.
Areas of Agreement / Disagreement
Participants generally agree on the relationship between RMS voltage and peak voltage, as well as the implications for transformer ratings. However, the discussion does not resolve the initial question regarding the factor of 1.41 in the context of fullwave bridge rectification.
Contextual Notes
The discussion does not address potential limitations or assumptions regarding the specific conditions under which the voltage factor applies, such as the characteristics of the load or the specific configuration of the rectifier circuit.
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