Why Does the Curl Calculation in Cylindrical Coordinates Include a Factor of r?

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Homework Help Overview

The discussion revolves around the calculation of the curl of a vector field in cylindrical coordinates, specifically focusing on the expression for the vector \(\bm{B}\) and the role of the factor \(r\) in the differentiation process.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the derivation of the curl in cylindrical coordinates, questioning the presence of the factor \(1/r\) in the expression for \(\bm{B}\). Some express confusion about the differentiation of \(A_{\theta}\) with respect to \(r\) and the implications of the textbook's formulation.

Discussion Status

Participants are actively questioning the textbook's approach and comparing it with other resources. There is an acknowledgment of differing interpretations, and some participants are attempting to clarify their understanding of the curl operation in this context.

Contextual Notes

Some participants mention the independence of certain components of the vector field with respect to specific variables, which may influence the calculations. There is also a reference to the need for additional information to resolve the confusion surrounding the factor \(r\).

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Homework Statement



Determine the vector [tex]\bm{B}=\left(\frac{\partial A_{\theta}}{\partial r}-\frac{1}{r}\frac{\partial A_r}{\partial \theta}\right)\hat{\phi}[/tex]

[tex]A_r[/tex] and [tex]A_{\theta}[/tex] are the components of the basis vectors [tex]\hat{r}[/tex] and [tex]\hat{\theta}[/tex].

The Attempt at a Solution



I just calculated the differentials in the expression for B above, but that gave me a factor [tex]1/r[/tex] too much in the answer. My textbook rewrites B as

[tex]\bm{B}=\frac{1}{r}\left(\frac{\partial (A_{\theta}r)}{\partial r}-\frac{\partial A_r}{\partial \theta}\right)\hat{\phi}[/tex].

They've broken out a factor [tex]1/r[/tex] before differentiating, but I don't understand the

[tex]\frac{\partial (A_{\theta}r)}{\partial r}[/tex]

part. Why isn't it

[tex]r\frac{\partial (A_{\theta})}{\partial r}[/tex]?
 
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I agree with you and I don't agree with the textbook.
 
Dick said:
I agree with you and I don't agree with the textbook.

Unfortunately for us, I have another textbook that agrees with the first. I don't think it's likely that two professional physicists makes exactly the same mistake on such a (I guess) basic thing.
 
Well, if I put A_theta=1 and A_r=1, I certainly don't get the same result for B for the two expressions. That's about all I can say.
 
Dick said:
Well, if I put A_theta=1 and A_r=1, I certainly don't get the same result for B for the two expressions. That's about all I can say.

I know, it's a mystery. Perhaps I should provide some more information. B is the cross product of the operator del and another vector, A, expressed in polar coordinates (B is only a function of [tex]r[/tex] and [tex]\theta[/tex]).
 
It sounds like you are computing the curl of A. If you are working in cylindrical coordinates, and A is independent of z, and the z component of A is independent of r and theta, then your second expression is the curl if you replace the theta hat with a z hat. That's a near as I can get to figuring out what you are up to. http://mathworld.wolfram.com/CylindricalCoordinates.html
 
Dick said:
It sounds like you are computing the curl of A. If you are working in cylindrical coordinates, and A is independent of z, and the z component of A is independent of r and theta, then your second expression is the curl if you replace the theta hat with a z hat. That's a near as I can get to figuring out what you are up to. http://mathworld.wolfram.com/CylindricalCoordinates.html

Yes, it's the curl I'm trying to calculate. I see now that I've been working with an incorrect http://hyperphysics.phy-astr.gsu.edu/Hbase/curl.html#c2". I still don't know where the factor [tex]r[/tex] in front of [tex]\bm{E}_\theta[/tex] in the determinant (see the link I provided) comes from, though.
 
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