Why does the pressure of a gas bubble change as it rises?

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SUMMARY

The discussion centers on the pressure changes of a gas bubble as it rises in a fluid. The final pressure of the bubble is determined by the equation 'final pressure = initial pressure x (R^3/r^3)', maintaining constant PV conditions. The pressure exerted by the gas inside the bubble does not directly affect the initial and final pressure values, as these values account solely for submerged pressure and atmospheric pressure. The equilibrium between the outward pressure of the gas and the inward pressure of the fluid is explained through Newton's third law, emphasizing that the bubble's volume changes to maintain pressure balance as it ascends.

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TomK
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Homework Statement
ENGAA 2019 (Q8, Section 2)
Relevant Equations
Pressure Equations
Ideal Gas Laws
Q8 (Section 2) - Imgur.jpg
Q8 (Section 2) - New Working.jpg
Q8 (Section 2) - New Working 2.jpg


The correct answer is 'C'.

I'm having trouble understanding the solution shown on this link (http://www.engineeringadmissionsassessment.com/2019-solutions.html) - scroll down to Section 2, Question 8.

From what I've gathered, [final pressure = initial pressure x 'R^3/r^3'], as PV must be constant. Therefore, I understand why they equate 'R^3/r^3' to 'final pressure/initial pressure'.

However, why doesn't the pressure exerted by the gas (within the bubble) affect the values of the initial and final pressure, since the bubble's volume is changing as it rises? Doesn't the pressure exerted by the gas (outward) oppose the pressure exerted on the gas (inward) by the liquid and atmospheric pressure?

In the solution, it looks like their initial/final pressure values only account for the 'pressure due to being submerged' and 'atmospheric pressure'. This is what I'm getting confused by.
 
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TomK said:
Doesn't the pressure exerted by the gas (outward) oppose the pressure exerted on the gas (inward) by the liquid and atmospheric pressure?
Newton's third law.

The outward pressure of the gas in the bubble on the fluid outside is exactly equal to the inward pressure of the fluid outside on the gas inside.

The two forces are not "opposed". They are part and parcel of the same force pair.
 
jbriggs444 said:
Newton's third law.

The outward pressure of the gas in the bubble on the fluid outside is exactly equal to the inward pressure of the fluid outside on the gas inside.

The two forces are not "opposed". They are part and parcel of the same force pair.

So, as the bubble rises from the base to the given height, the bubble changes volume, in order for the pressure outside = pressure inside?
 
TomK said:
So, as the bubble rises from the base to the given height, the bubble changes volume, in order for the pressure outside = pressure inside?
Yes.

If pressure inside had remained the same while pressure outside declined, the fluid at the boundary would be under an unbalanced net force. The bubble would expand, forcing that fluid outward.

Which is exactly what happens. The fluid is forced outward, the bubble expands, its volume increases and its pressure declines so that a new equilibrium is attained.
 
jbriggs444 said:
Yes.

If pressure inside had remained the same while pressure outside declined, the fluid at the boundary would be under an unbalanced net force. The bubble would expand, forcing that fluid outward.

Which is exactly what happens. The fluid is forced outward, the bubble expands, its volume increases and its pressure declines so that a new equilibrium is attained.

Thank you for helping.
 

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