Why Does the Voltage Across a Capacitor Lag Behind the Input Voltage?

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SUMMARY

The voltage across a capacitor (V0) lags the input voltage (Vi) by 90 degrees due to the phase relationship between current and voltage in an AC circuit. In this discussion, the reference phase is set at 0 degrees for the current (I), which is in phase with the voltage across the resistor (R). The analysis demonstrates that while the voltage across the resistor is in phase with the current, the capacitor voltage lags behind the current, resulting in Vi leading V0. This relationship is confirmed through vector diagrams and is foundational in understanding AC circuit behavior.

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Homework Statement



Can somebody explain why the voltage across the capacitor (v0) lags vi?


Homework Equations





The Attempt at a Solution


 

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I proved it with a vector diagram.
Let I be the reference phase ie. 0 degrees. Because the voltage across R is in phase with I it also has 0 phase.
The capacitor voltage V0 lags I by 90 degrees ie. -90
Vi=V0+Rvoltage.
This shows Vi vector after I (R voltage) but before V0.
Therefore Vi leads V0.

I still would appreciate a more intuitive explanation if somebody has one.
 
My old ARRL handbook explained this in a non-calculus way. I never bothered to try to understand it. It was obvious to me once I had diff eq's and transform techniques - meanwhile, I believe yours is the best intuitive explanation there is.
 

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