Why Does Zitterbewegung Imply Double the Expected Relativistic Energy?

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From this http://arxiv.org/abs/1411.1854
And $$E=\hbar\omega$$ We get $$E=2mc^2$$

Which is twice the relativistic energy. Why is that ?
 
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jk22 said:
From this http://arxiv.org/abs/1411.1854
And $$E=\hbar\omega$$ We get $$E=2mc^2$$

Which is twice the relativistic energy. Why is that ?

At the top of the second page, they define zitter:
The angular frequency at which a particle zitters is given by twice the de Broglie electron clock rate as determined in his 1924 dissertation.

The ω which you plug into the equations is the zitter frequency, which is why your relativistic energy expression is wrong.
 
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