Why Is Achieving Orbit Considered Halfway to Anywhere?

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SUMMARY

The discussion centers on the concept that achieving low Earth orbit (LEO) at an altitude of 400 km is a critical milestone in space travel, as articulated by Robert Heinlein. The minimum energy required to place a satellite into LEO is significantly less than the energy needed to escape Earth's gravitational pull entirely. The equations governing kinetic energy (KE) and gravitational potential energy (U) illustrate that while mass (m) influences total energy, escape velocity remains constant at approximately 7 miles per second, independent of mass. By setting total energy (E) to zero, one can derive the escape velocity without needing the satellite's mass.

PREREQUISITES
  • Understanding of gravitational potential energy (U) and kinetic energy (KE)
  • Familiarity with the concepts of escape velocity and low Earth orbit (LEO)
  • Basic knowledge of Newton's law of universal gravitation
  • Proficiency in algebraic manipulation of equations
NEXT STEPS
  • Study the derivation of escape velocity using gravitational potential energy equations
  • Explore the implications of achieving low Earth orbit on satellite deployment
  • Investigate energy requirements for different orbital altitudes beyond LEO
  • Learn about the effects of air resistance on satellite launch trajectories
USEFUL FOR

Aerospace engineers, physicists, students of astrophysics, and anyone interested in the principles of orbital mechanics and space travel.

dswatson
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The science fiction writer Robert Heinlein once said, "If you can get into orbit, then you're halfway to anywhere". Justify this statement by comparing the minimum energy needed to place a satellite into low Earth orbit (h=400km) to that needed to set it completely free from the bonds of Earth's gravity. Neglect any effects due to air resistance.

E = KE + U
E = 1/2mv^2 + U
U = -(int)[F*dr]
U = -G(Mm/r^2)
E = m( (1/2)v^2 - G(M/r^2)

m = mass satellite
M = mass earth

Im stuck because I am not given a mass for the satellite and I know that excape velocity does not depend on mass. It is approxmately 7mi/s but I am unsure of how to show that energy is not mass dependent and then solving for the equation with no mass.
 
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Well, first of all, the total energy is

[tex]E = m\left( \frac{v^2}{2} - \frac{GM}{r}\right)[/tex]

(you got the power wrong). It depends on m, but if you set it equal to zero E=0, then m cancels and you can solve for v without knowing m.
 

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