Why is average velocity=(v+u)/2

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Discussion Overview

The discussion centers around the concept of average velocity in the context of uniform acceleration, specifically addressing the formula average velocity = (v + u) / 2. Participants seek to understand the reasoning behind this formula without relying solely on standard kinematic equations.

Discussion Character

  • Conceptual clarification
  • Exploratory

Main Points Raised

  • One participant asks for clarification on why average velocity can be expressed as (v + u) / 2, noting their understanding of averages but seeking deeper insight.
  • Another participant provides a derivation using kinematic equations, showing how average velocity can be calculated from displacement and time.
  • A later reply emphasizes that a common sense approach can explain the average velocity for uniformly changing velocity, using an analogy of average height on a flat incline.
  • Some participants express frustration with the forum's formatting issues, which distract from the discussion.

Areas of Agreement / Disagreement

Participants generally agree that the formula for average velocity can be understood through both mathematical derivation and intuitive reasoning. However, there is no consensus on the necessity of using kinematic equations versus a common sense approach.

Contextual Notes

Some participants mention the limitations of the forum software affecting readability, which may impact the clarity of the discussion.

bloodhound
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Hi,

I am reading through a study guide and currently going through the kinematics section.

In the section on uniform acceleration it gives all the standard formulae and explains how they are derived.

It says that average velocity = s/t, but also that it is equal to (v+u)/2 if the average velocity is uniform.
Can someone explain this second part to me please? I understand the concept of averages and that we are dividing by 2 because we are only using 2 values, v and u. But through explaining the concept how does adding together v and u bring us the average velocity?

Thanks.
 
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How about this:
v = u + at (or: at = v - u)

s = ut + 1/2at^2
ave velocity = s/t = (ut + 1/2at^2)/t = u + 1/2at = u + 1/2(v - u) = (v+u)/2.
 
Doc Al said:
How about this:
v = u + at (or: at = v - u)

s = ut + 1/2at^2
ave velocity = s/t = (ut + 1/2at^2)/t = u + 1/2at = u + 1/2(v - u) = (v+u)/2.

Yes that makes sense, thanks.

However in the book, it seems like it is saying that through a common sense approach this can be explained; i.e. not through using the other formulae.

Here is how it is written in the book:

DSC00205.jpg

DSC00206.jpg

DSC00207.jpg
 
Does the forum software have a trim option to prevent this?
 
It is the 3rd picture which contains the sentence that is causing me grief.
It says 'Since the velocity is changing uniformly we know that this average velocity must be given by:

average velocity = (v+u)2.

Without using the other equations of uniform motion, why is this the case, why must it be given by (v+u)/2?
 
Phrak said:
Does the forum software have a trim option to prevent this?

To prevent what?
 
bloodhound said:
However in the book, it seems like it is saying that through a common sense approach this can be explained; i.e. not through using the other formulae.
There's nothing wrong with that. If something varies uniformly (linearly) that reasoning is fine. For example, if a flat incline goes from a height of 5 m to 25 m, what's the average height? Right in the middle, which is (5 + 25)/2 = 15 m.
 
Phrak said:
Does the forum software have a trim option to prevent this?

bloodhound said:
To prevent what?

To prevent oversized attachments from messing up the formatting. (Which makes the posts harder to read.)

I've seen this happen quite a bit. (I'll report it to the admins to see if there's a solution.)
 
Last edited:
Doc Al said:
To prevent oversized attachments from messing up the formatting. (Which makes the posts harder to read.)

I've seen this happen quite a bit.

Oh right, sorry I should have reduced the size. Maybe I can edit it still?
 

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