Why is average velocity=(v+u)/2

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The discussion centers on understanding why average velocity in uniformly accelerated motion is calculated as (v + u)/2. The user seeks clarification on how this formula represents average velocity without relying on other kinematic equations. It is explained that when velocity changes uniformly, the average can be intuitively understood as the midpoint between the initial (u) and final (v) velocities. An analogy is provided comparing average height on a slope to reinforce this concept. The conversation also touches on formatting issues within the forum, unrelated to the main topic.
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Hi,

I am reading through a study guide and currently going through the kinematics section.

In the section on uniform acceleration it gives all the standard formulae and explains how they are derived.

It says that average velocity = s/t, but also that it is equal to (v+u)/2 if the average velocity is uniform.
Can someone explain this second part to me please? I understand the concept of averages and that we are dividing by 2 because we are only using 2 values, v and u. But through explaining the concept how does adding together v and u bring us the average velocity?

Thanks.
 
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How about this:
v = u + at (or: at = v - u)

s = ut + 1/2at^2
ave velocity = s/t = (ut + 1/2at^2)/t = u + 1/2at = u + 1/2(v - u) = (v+u)/2.
 
Doc Al said:
How about this:
v = u + at (or: at = v - u)

s = ut + 1/2at^2
ave velocity = s/t = (ut + 1/2at^2)/t = u + 1/2at = u + 1/2(v - u) = (v+u)/2.

Yes that makes sense, thanks.

However in the book, it seems like it is saying that through a common sense approach this can be explained; i.e. not through using the other formulae.

Here is how it is written in the book:

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Does the forum software have a trim option to prevent this?
 
It is the 3rd picture which contains the sentence that is causing me grief.
It says 'Since the velocity is changing uniformly we know that this average velocity must be given by:

average velocity = (v+u)2.

Without using the other equations of uniform motion, why is this the case, why must it be given by (v+u)/2?
 
Phrak said:
Does the forum software have a trim option to prevent this?

To prevent what?
 
bloodhound said:
However in the book, it seems like it is saying that through a common sense approach this can be explained; i.e. not through using the other formulae.
There's nothing wrong with that. If something varies uniformly (linearly) that reasoning is fine. For example, if a flat incline goes from a height of 5 m to 25 m, what's the average height? Right in the middle, which is (5 + 25)/2 = 15 m.
 
Phrak said:
Does the forum software have a trim option to prevent this?

bloodhound said:
To prevent what?

To prevent oversized attachments from messing up the formatting. (Which makes the posts harder to read.)

I've seen this happen quite a bit. (I'll report it to the admins to see if there's a solution.)
 
Last edited:
Doc Al said:
To prevent oversized attachments from messing up the formatting. (Which makes the posts harder to read.)

I've seen this happen quite a bit.

Oh right, sorry I should have reduced the size. Maybe I can edit it still?
 
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