Why is component reverse in Conical Pendulum?

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Homework Help Overview

The discussion revolves around the conical pendulum, specifically the confusion regarding the components of tension in relation to the angle θ. Participants are exploring the trigonometric relationships that define the x and y components of the forces acting on the pendulum bob.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are questioning the assignment of sine and cosine to the x and y components of tension. There is a discussion about the angle θ and its relation to the x-axis, with some suggesting that the orientation of the angle affects which trigonometric function applies.

Discussion Status

The conversation is actively exploring different interpretations of the trigonometric components. Some participants have provided guidance on constructing right triangles to clarify the relationships, and there is an acknowledgment that the x component can vary depending on the angle's reference point.

Contextual Notes

There is an emphasis on understanding the geometry of the situation, with references to diagrams and the need for clarity on the center of circular motion. The original poster expresses confusion about the teacher's feedback on their equations, indicating a lack of consensus on the correct approach.

soccer5454
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Hello. In class today, we studied conical pendulum but I was confused at the part about its components. In all the diagrams ( http://dev.physicslab.org/img/90c0fb7a-ffb4-4573-b389-b50a559732c8.gif ) if shows The x-component as being sine, but I always thought x-comp was cos?? ( http://faculty.ccbcmd.edu/~jzelinsk/phys_101/chapter3/chapter3.htg/img2.gif )
Also for equations I made them

T cos(θ) = mv2/r
T sin(θ) = mg

But teacher say it is wrong and it should be other way but I don't understand, please help!
 
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Often the direction of a vector is specified by the angle the vector makes with respect to the x axis, as in your second link. What about θ in your first link?
 
But even it was at a different spot, wouldn't the horizontal always be cos?
 
Look at the figure below. How would you use trig to find the lengths of the green and red sides of the triangle?
 

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  • conical pend.png
    conical pend.png
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Green would be sin and red would be cos. so

T cos(θ) = mv2/r
T sin(θ) = mg
 
soccer5454 said:
Green would be sin and red would be cos.
Yes, that's right.
so
T cos(θ) = mv2/r
T sin(θ) = mg

Which side of the triangle "points toward the center" of the circular motion of the pendulum bob?
 
Red line I believe
 
Where is the center of the circular motion in the picture in your first link? Is it to the left of the mass, to the right of the mass, above the mass, or below the mass?
 
I think its to the left
 
  • #10
Yes.

So, according the the figure below, which component of the tension points toward the center of the circular motion? The green component or the red component?
 

Attachments

  • conical pend 3.png
    conical pend 3.png
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  • #11
Green comp
 
  • #12
Yes. So, which component should be set equal to mv2/r?
 
  • #13
sine!:)
 
  • #14
Good.
 
  • #15
Just a quick question,so the x-comp can always change? So it is not always cos or sin but it depends on where the center of motion is right?
 
  • #16
The x component is not always obtained by using cos(θ). It depends on whether or not θ is measured from the x axis. Whenever you are in doubt, construct a right triangle and use trig to get the x and y components.
 
  • #17
TSny said:
The x component is not always obtained by using cos(θ). It depends on whether or not θ is measured from the x axis. Whenever you are in doubt, construct a right triangle and use trig to get the x and y components.
Oh ok got it thanks :)
 

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