Why is displacement used in the formula for velocity instead of distance?

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SUMMARY

The discussion clarifies that the formula for Average Velocity is defined as Displacement divided by Elapsed Time, emphasizing the importance of displacement as a vector quantity. Unlike distance, which is a scalar and does not account for direction, displacement considers the overall change in position. This distinction is crucial in scenarios where an object returns to its starting point, resulting in zero displacement and thus zero average velocity, despite potentially high average speed. The conversation highlights the fundamental difference between vector and scalar quantities in physics.

PREREQUISITES
  • Understanding of vector and scalar quantities in physics
  • Basic knowledge of the formula for Average Velocity
  • Familiarity with the concepts of displacement and distance
  • Knowledge of elapsed time measurement
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  • Study the differences between vector and scalar quantities in physics
  • Learn about the implications of displacement in kinematics
  • Explore the concept of average speed versus average velocity
  • Investigate real-world applications of velocity in physics problems
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Students learning physics, educators teaching kinematics, and anyone interested in understanding the principles of motion and velocity calculations.

Taterpeel
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Hello everyone. I want to learn Physics, so I've been trying to teach myself. I still don't know much, and am just now getting to the formula for Velocity. The internet tutorial I am using says it is this..

Average Velocity = Displacement / Elapsed Time

And I've been plugging in the numbers, and it's not hard or anything. I was just wondering.. Why would displacement be in the numerator? Shouldn't it be distance? If I travel somewhere and then travel back to my destination 30 times in an hour, won't my velocity be different than if I do it 5 times? But I will end up with the same Displacement, so why do I use displacement here, and not distance?
 
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Velocity is a vector quantity. It includes direction. So if you travel around and eventually end up where you started, your average velocity was zero.

Ie, if you travel one direction for an hour at 60 mph and travel back to where you started also at 60 mph, that's 60*1+(-60)*1=0 displacement. Average velocity is (60+(-60))/2=0 But speed is a scalar quantity, so your average speed is (60+60)/2=60.
 

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