Why is my 555 Timer not blinking?

  • Thread starter Thread starter Twinfun2
  • Start date Start date
  • Tags Tags
    555 timer Timer
Click For Summary
The user is experiencing issues with a 555 timer circuit designed to blink an LED, as the LED remains constantly on and the timer overheats. Key troubleshooting steps include verifying the wiring, ensuring the LED is connected correctly between pin #3 and ground, and checking the current-limiting resistor value. The user is using a 6V power supply with an NE555N timer, which should operate within safe voltage limits, but overheating suggests a possible short circuit or incorrect connections. Recommendations include checking for loose connections, testing the capacitor, and ensuring no shorts exist in the circuit, as prolonged overheating can damage the timer.
  • #31
Check that the power source + only goes to pins 4 and 8 of the 555 and does not go to pin 3. Make sure the polarity is right.

Note that pins 4 and 8 are diagonally opposite each other on the chip.
Pins number anticlockwise around the chip starting at the top left if you look at the top of the chip with the notch at the top.

You can do this without applying power. The chip may have blown up already, so don't put a new one in until you find the fault.

See this link from a few weeks ago. There are pictures of a similar setup and a list of voltage measurements.
https://www.physicsforums.com/showthread.php?t=311178
 
Engineering news on Phys.org
  • #32
vk6kro said:
Check that the power source + only goes to pins 4 and 8 of the 555 and does not go to pin 3. Make sure the polarity is right.

Note that pins 4 and 8 are diagonally opposite each other on the chip.
Pins number anticlockwise around the chip starting at the top left if you look at the top of the chip with the notch at the top.

You can do this without applying power. The chip may have blown up already, so don't put a new one in until you find the fault.

See this link from a few weeks ago. There are pictures of a similar setup and a list of voltage measurements.
https://www.physicsforums.com/showthread.php?t=311178

Yes, I checked so many times if my connections were correct that I'm beginning to stutter when I say "555".

I have checked that thread before I posted here but the poster's solution is inapplicable to my setup; I have the correct resistors.

POSSIBLY USEFUL INFORMATION: When I use a 9v battery supply instead of my 4xAA battery 6v supply, the circuit doesn't work at all! The timer doesn't warm up or anything! From what I understand, the timer should work exactly the same way as it would the 6v supply; correct me if I'm wrong.

Driving to philly, I'll be back in 2 hours perhaps.
 
  • #33
Are you going to plug in a new 555 to see if it works?

How about unplugging the present 555 and measuring the voltages on all the pins relative to the negative terminal on the battery? A multimeter, especially a digital one, is fine for this. Just poke a piece of wire into the socket holes to measure the voltages.

Make a list of 8 voltages from pin 1 to pin 8.
Put the list here if you can't see already what is wrong.

That should tell you if it is safe to put the new chip into the circuit.

You should get a list like this with a 6 v supply.
1 0V
2 6V
3 0V
4 6V
5 0V
6 6V
7 6V
8 6V
Pins 6 and 2 could be a bit lower depending on your multimeter's internal resistance. Maybe 5.4 V if the meter is a digital with 1 M input resitance because of the 100 K in series.

Your 9 V battery probably can't deliver much current into a short circuit so it doesn't cause heating.
 
  • #34
vk6kro said:
Are you going to plug in a new 555 to see if it works?

How about unplugging the present 555 and measuring the voltages on all the pins relative to the negative terminal on the battery? A multimeter, especially a digital one, is fine for this. Just poke a piece of wire into the socket holes to measure the voltages.

Make a list of 8 voltages from pin 1 to pin 8.
Put the list here if you can't see already what is wrong.

That should tell you if it is safe to put the new chip into the circuit.

You should get a list like this with a 6 v supply.
1 0V
2 6V
3 0V
4 6V
5 0V
6 6V
7 6V
8 6V
Pins 6 and 2 could be a bit lower depending on your multimeter's internal resistance. Maybe 5.4 V if the meter is a digital with 1 M input resitance because of the 100 K in series.

Your 9 V battery probably can't deliver much current into a short circuit so it doesn't cause heating.

When I get home, I will do this for sure, but I am not quite sure if I understand how to do what your saying 100%.

"How about unplugging the present 555 and measuring the voltages on all the pins relative to the negative terminal on the battery? A multimeter, especially a digital one, is fine for this. Just poke a piece of wire into the socket holes to measure the voltages."

Can you be a little more specific? I don't understand what you mean by socket holes, or what you mean by measuring the voltages on all the pins relative to the negative terminal on the battery. Do I just remove the 555 and test an incomplete circuit with the multimeter? Because from what I understand, no voltage can travel through an incomplete circuit. :rolleyes:

Sorry about being so newbie, but I simply don't understand what you mean. :frown:

But yes, I have a new 555 timer, but I will first do what you recommend (once I figure out exactly how) before inserting the new timer.

Thank you so much for your patience! :!)
 
  • #35
Twinfun2 said:
Can you be a little more specific? I don't understand what you mean by socket holes, or what you mean by measuring the voltages on all the pins relative to the negative terminal on the battery. Do I just remove the 555 and test an incomplete circuit with the multimeter? Because from what I understand, no voltage can travel through an incomplete circuit. :uhh

Yes, just leave the chip out (but all the ancillary components in place) and check the voltages at the points where the pins of the chip would be. No, the circuit won't function under these conditions, but you will still have some voltages, either directly from +Vs or through a resistor.
 
  • #36
negitron said:
Yes, just leave the chip out (but all the ancillary components in place) and check the voltages at the points where the pins of the chip would be. No, the circuit won't function under these conditions, but you will still have some voltages, either directly from +Vs or through a resistor.

Good deal; makes sense now. I'll post right after I get the ratings.
 
  • #37
Rule of thumb - if the part gets too hot for comfort than it either needs a heatsink or you are doing something wrong (like reverse the polarity). For many chips if your reverse the polarity it will act as a short and will heat up very quickly.

Does your voltmeter have a current measuring ability? If so, try with that (making sure that you connect it in SERIES). Now, also disconnect everything and connect only power and ground and see if it gets even warm. If so then somethign is bad there.
 
  • #38
The 555 is especially vulnerable to external voltage on pin 3, its output.
So, it is important not to plug a new chip in if there is voltage on this socket pinhole.


I found a great website on 555 applications. Sometimes someone just does a superb job with making a website and this is one of them.
http://www.uoguelph.ca/~antoon/gadgets/555/555.html

Anyone here could probably fix that circuit in a few minutes but it can take hours on this Forum to ask the right questions without seeming to be insulting. So, please excuse any questions that seem to be too simple.

I have a couple of breadboards , but I prefer to solder up a circuit on a bit of printed circuit board.
Maybe you would like to try it. You turn the chip so its legs are facing upwards. (this construction method is called "dead bug construction" for this reason).
Any legs that are to be grounded are bent downwards and soldered to the PC board. Also any capacitors etc that need to be grounded are soldered in.
Power leads etc are attached to tag strips and not directly to the IC. (I use header pins cut to shape as tag strips).
This way, you can lay out a circuit as it is in a diagram and quickly see if something is wrong. It is very safe and the IC is in no danger of being pulled apart. And you can easily change a component value if you want to.
 
Last edited by a moderator:
  • #39
ShadowPho1 said:
Rule of thumb - if the part gets too hot for comfort than it either needs a heatsink or you are doing something wrong (like reverse the polarity). For many chips if your reverse the polarity it will act as a short and will heat up very quickly.

Does your voltmeter have a current measuring ability? If so, try with that (making sure that you connect it in SERIES). Now, also disconnect everything and connect only power and ground and see if it gets even warm. If so then something is bad there.

Well, I think it's possible that this would explain my problem. After I only connected the V+ and 0v, it still got very hot (people who can verify this will be greatly appreciated)! I guess the bottom line would be that the timer is down right fried/defective. Before I plug in my new timer, I'm going to take a few pictures of my bread boarded circuit before I go ahead and connect the 6v supply.

Again, thank you all for being of so much help! :!)
 
  • #40
vk6kro said:
I have a couple of breadboards , but I prefer to solder up a circuit on a bit of printed circuit board.
Maybe you would like to try it. You turn the chip so its legs are facing upwards. (this construction method is called "dead bug construction" for this reason).
Any legs that are to be grounded are bent downwards and soldered to the PC board. Also any capacitors etc that need to be grounded are soldered in.
Power leads etc are attached to tag strips and not directly to the IC. (I use header pins cut to shape as tag strips).
This way, you can lay out a circuit as it is in a diagram and quickly see if something is wrong. It is very safe and the IC is in no danger of being pulled apart. And you can easily change a component value if you want to.

Does current travel differently in a soldered circuit than in a bread boarded circuit? And also a question, I mind as well ask, in relation is: Can the magnetic field of electricity traveling in a bread boarded circuit be severe enough to effect activity going on in adjacent bus stripes in the bread board?
 
  • #41
Twinfun2 said:
And also a question, I mind as well ask, in relation is: Can the magnetic field of electricity traveling in a bread boarded circuit be severe enough to effect activity going on in adjacent bus stripes in the bread board?

Nah, the breadboard will melt long before there's enough current to create large magnetic fluxes. :smile:
 
  • #42
Does current travel differently in a soldered circuit than in a bread boarded circuit?

No, but the connections are more secure, you can see the whole circuit and wire lengths are shorter meaning you get less inductance in the circuit.

Inductance of a few inches of wire doesn't matter for a 555 light flashing circuit but for any serious circuits at high frequencies, it can mean the difference between a circuit working or not working.
For example, I just measured the reactance of a 4 inch piece of wire at 15 MHz. It had a reactance of 17 ohms. That would be enough to upset most circuits operating at that frequency.

Can the magnetic field of electricity traveling in a bread boarded circuit be severe enough to effect activity going on in adjacent bus stripes in the bread board?


Two such wires anywhere near each other at high frequencies would behave like a transformer and pass power from one to the other and possibly cause an amplifier to oscillate.

At VHF (frequencies above 30 MHz) construction techniques that involve short wire lengths are very important and I build all equipment as if it was for VHF. Good ground planes and short wires on components. It is a good habit to get into.
 
  • #43
vk6kro said:
Two such wires anywhere near each other at high frequencies would behave like a transformer and pass power from one to the other and possibly cause an amplifier to oscillate.


I think we can agree that this is way too small an effect to be of concern here to Twinfun2. :smile:

Twinfun2, what you have is some kind of very large current flowing through your device, either from the supply terminals, or through the output pin (which appears to be the only pin which is not internally current-limited in the NE555N).

- Warren
 
  • #44
The poster did ask about the effect of lead length.
Can the magnetic field of electricity traveling in a bread boarded circuit be severe enough to effect activity going on in adjacent bus stripes in the bread board?

Even if you are making an audio amplifier, most transistors these days can operate at 300 MHz or more and they may well oscillate at those frequencies if the layout is poor.

I used a 2N3563 in a battery charger for NiMH batteries recently. This transistor has a ft of 900 MHz, so I cut the leads very short to try to avoid parasitic oscillation. Good layout never goes astray.

I am hoping the fault will be a wiring error or a faulty IC, but VHF oscillation is a real problem in breadboard circuitry. The 555 may not operate there but it has transistors in it that probably can. It can produce some pretty fast square wave edges.
 
  • #45
At the frequencies Twinfun2 is using, a 555 should work just fine on a solderless breadboard.
 
  • #46
Twinfun2 said:
Well, I think it's possible that this would explain my problem. After I only connected the V+ and 0v, it still got very hot (people who can verify this will be greatly appreciated)!

Still wanting to know if this means that the timer is officially bad.

EDIT: I'm still trying to get a hold of a camera :mad:. I'll wind up drawing my bread board circuit layout on paint or something.
 
Last edited:
  • #47
Here are my pin ratings according to instruction given by vk6kro, and negitron.

For Reference:
__________

R1:10k
R2:100k
C:10uF
__________

1: 0v
2: 2v
3: 0v
4: 5v
5: 0v
6: 2v
7: 4.5v
8: 5v

(I'm, sadly, using an analog multimeter, and those are the best ratings I have been able to grab.)
 
  • #48
Twinfun2 said:
Still wanting to know if this means that the timer is officially bad.

Yes, the part is bad.

- Warren
 
  • #49
chroot said:
Yes, the part is bad.

- Warren

Muchos gracias. :biggrin:

Now just awaiting if those volt readings are correct, or near correct, before inserting my new timer.
 
  • #50
Twinfun2 said:
3: 0v

This worries me. Pin #3 is the output pin, which supplies current to the load. If nothing is connected to it, it should be floating, and will probably not go all the way down to 0V. If you've connected pin #3 to your LED and resistor, it should have a voltage of around 4-5V on it.

If pin #3 is really all the way down at ground (0V), then a huge amount of current is likely flowing out of it. Something's screwed up with that pin. Disconnect everything from it, and make absolutely sure there's no continuity between it and the ground rail.

- Warren
 
  • #51
chroot said:
This worries me. Pin #3 is the output pin, which supplies current to the load. If nothing is connected to it, it should be floating, and will probably not go all the way down to 0V. If you've connected pin #3 to your LED and resistor, it should have a voltage of around 4-5V on it.

If pin #3 is really all the way down at ground (0V), then a huge amount of current is likely flowing out of it. Something's screwed up with that pin. Disconnect everything from it, and make absolutely sure there's no continuity between it and the ground rail.

- Warren

The way I was told to do it was to disconnect the timer, and place wires where the pins would be, and to read those wires compared to a ground with a multimeter.
 
  • #52
Oh, I see, you removed the timer and those are the voltages on the pins without it present.

Is there any chance that your breadboard is damaged, and there's a short in it that you don't expect? Do you have a multimeter with continuity testing?

At this point, I'd suggest that you dismantle the circuit, and build it again somewhere else on the breadboard. I'd start with just the VCC, RESET, and GND pins, make sure the part doesn't get hot, and then move on to connecting the rest of the circuit.

- Warren
 
  • #53
chroot said:
Oh, I see, you removed the timer and those are the voltages on the pins without it present.

Is there any chance that your breadboard is damaged, and there's a short in it that you don't expect? Do you have a multimeter with continuity testing?

At this point, I'd suggest that you dismantle the circuit, and build it again somewhere else on the breadboard. I'd start with just the VCC, RESET, and GND pins, make sure the part doesn't get hot, and then move on to connecting the rest of the circuit.

- Warren

The word continuity causes my head to make buzzy sounds! :eek:

In other words, what's continuity? (EDIT: Wow, someone explained that to me already in this very thread...the real question: How do I use the multimeter to test continuity?)

This is my multimeter:
http://www.radioshack.com/product/index.jsp?productId=2103170&tab=summary

Also, I just got a hold of a digital camera; going to take as many good shots as possible. I'll be posting them within the next hour or two.
 
  • #54
Ok, I just reconnected everything in a new place, and she is ready for her photo shoot! :smile:
 
  • #55
Twinfun2 said:
In other words, what's continuity? (EDIT: Wow, someone explained that to me already in this very thread...the real question: How do I use the multimeter to test continuity?)

Typically, you turn your multimeter's control dial to the position with a little speaker icon. Next, you touch two different spots with the probes (it doesn't matter which way 'round they are connected). If there is a very low-resistance path between the spots, the meter will beep, letting you know the two spots are electrically the same.

You want to make sure there is no direct connection between pin #3 (output) and any other pin, particularly VCC or GND.

- Warren
 
  • #56
Twinfun2 said:
How do I use the multimeter to test continuity?)

chroot said:
Typically, you turn your multimeter's control dial to the position with a little speaker icon. Next, you touch two different spots with the probes (it doesn't matter which way 'round they are connected). If there is a very low-resistance path between the spots, the meter will beep, letting you know the two spots are electrically the same.

Since the OP's http://rsk.imageg.net/graphics/uc/rsk/Support/ProductManuals/2200223_PM_EN.pdf" does not mention continuity measurement, he can just measure the resistance and look for a (nearly) zero-ohm reading to indicate that two locations are connected, or an infinite-ohm reading to indicate that they are not.
 
Last edited by a moderator:
  • #57
As far as I can tell, nobody has posted any schematic of a NE555 LED oscillator. So I built one in 15 minutes (in LTSpice) and turned it on. Here it is...
 

Attachments

  • NE555­_LED_Osc.jpg
    NE555­_LED_Osc.jpg
    53.9 KB · Views: 557
  • #58
_______________________________________________

The Pictures: (Picture One Indicates Pin 1)

http://img265.imageshack.us/gal.php?g=oneh.jpg

For Reference:
__________

R1:10k
R2:100k
C:10uF

_______________________________________________
 
  • #59
Looks like the LED+resistor are connected between pin 4 and ground, but it should be pin 3 and ground.

Since pin 4 is tied to Vs, the LED would stay on continuously.

EDIT: that would not have caused the chip to overheat however.
 
  • #60
Redbelly98 said:
Looks like the LED+resistor are connected between pin 4 and ground, but it should be pin 3 and ground.

Since pin 4 is tied to Vs, the LED would stay on continuously.

Just fixed.

(I didn't make that mistake before, so nothing wrong there. :blushing:)

Anything else?
 

Similar threads

  • · Replies 14 ·
Replies
14
Views
2K
Replies
16
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 38 ·
2
Replies
38
Views
22K
  • · Replies 6 ·
Replies
6
Views
4K
Replies
4
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 5 ·
Replies
5
Views
9K
Replies
5
Views
3K
  • · Replies 8 ·
Replies
8
Views
6K