Why Is My Approach to Solving Physics Homework Incorrect?

  • Thread starter Thread starter Garen
  • Start date Start date
Click For Summary

Homework Help Overview

The discussion revolves around a physics problem involving forces, tension, and motion, specifically focusing on the relationship between mass, acceleration, and velocity in a circular motion context.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to relate mass and acceleration to velocity using the equation ma = mv^2/r, but questions arise regarding the assumptions made about tension in the string and the forces acting in different planes.

Discussion Status

Participants are actively engaging in clarifying the original poster's approach, with some suggesting a need to reconsider the assumptions about tension and to apply Newton's second law to different planes. There is a focus on exploring the correct setup of equations rather than reaching a definitive solution.

Contextual Notes

There appears to be confusion regarding the forces involved, particularly the assumption that tension equals mg, which is being questioned. The problem is described as deceptively easy, indicating potential complexities in the setup.

Garen
Messages
28
Reaction score
0

Homework Statement


2qbgkr5.png



Homework Equations


5d423445741ddd2681bf2639f9b0bd89.png



The Attempt at a Solution



The way I understood is it is by taking ma and setting it equal to mv^2/r and solving for v. With this I got answer choice number 9, sqrt(glsinTHETA). But it's wrong. Can anyone direct me in the right direction to solving this deceptively easy problem? Thanks in advance.
 
Physics news on Phys.org
Garen said:

Homework Statement


2qbgkr5.png



Homework Equations


5d423445741ddd2681bf2639f9b0bd89.png



The Attempt at a Solution



The way I understood is it is by taking ma and setting it equal to mv^2/r and solving for v. With this I got answer choice number 9, sqrt(glsinTHETA). But it's wrong. Can anyone direct me in the right direction to solving this deceptively easy problem? Thanks in advance.
You're on the right lines. However, you incorrectly assume that the tension in the string is mg.
 
Hootenanny said:
You're on the right lines. However, you incorrectly assume that the tension in the string is mg.

So you're saying that I set mv^2/r equal g/cosTHETA ?
 
Garen said:
So you're saying that I set mv^2/r equal g/cosTHETA ?
No. Start by writing down two equations: one for the requirement of the sum of the forces in the vertical plane, and one for the sum of the forces in the horizontal plane. In otherwords, apply Newton's second law separately to the vertical and radial planes.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 20 ·
Replies
20
Views
3K
Replies
2
Views
1K
  • · Replies 12 ·
Replies
12
Views
2K
Replies
40
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 13 ·
Replies
13
Views
9K
  • · Replies 3 ·
Replies
3
Views
7K