Why Is My Calculation of the Dielectric Constant Incorrect?

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SUMMARY

The calculation of the dielectric constant for a dielectric material between two parallel plates with an area of 110 cm² and charges of 9.6 × 10-7 C results in a dielectric constant (k) of 2.3. The induced charge on each dielectric surface is calculated using the formula q' = q(1 - (1/k)), yielding a value of 5.4 × 10-7 C. The equations used include k = q/(E*A*ε0) and q' = q(1 - (1/k)). The discussion highlights the importance of correctly applying Gauss' law for non-conducting plates.

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roro0505
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the answer i keep getting is wrong ... help?

Homework Statement



Two parallel plates of area 110 cm2 are given charges of equal magnitudes 9.6 × 10-7 C but opposite signs. The electric field within the dielectric material filling the space between the plates is 4.2 × 106 V/m.

(a) Calculate the dielectric constant of the material.
(b) Determine the magnitude of the charge induced on each dielectric surface.


Homework Equations



k=q/(E*A*epsilon_0)

q'=q(1-(1/k))

The Attempt at a Solution



k=q/(E*A*epsilon_0)
=9.6E-7/(4.2E6*110E-4*8.85E-12)
=2.3

q'=q(1-(1/k))
=9.6E-7(1-(1/2.3))
=5.4E-7
 
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roro0505 said:
the answer i keep getting is wrong ... help?

Homework Statement



Two parallel plates of area 110 cm2 are given charges of equal magnitudes 9.6 × 10-7 C but opposite signs. The electric field within the dielectric material filling the space between the plates is 4.2 × 106 V/m.

(a) Calculate the dielectric constant of the material.
(b) Determine the magnitude of the charge induced on each dielectric surface.
It is not clear but I suspect that these are non-conducting plates, in which case Gauss' law is:

[tex]\oint E dA = E2A = \frac{Q}{k\epsilon_0}[/tex]

AM
 

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