Why Is P1A1 Considered Positive in Fluid Force Calculations?

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Homework Help Overview

The discussion revolves around the interpretation of the force exerted on fluid in a pipe, specifically focusing on the term P1A1 in the equation P1A1 – Fx – P2A2. Participants are questioning why P1A1 is considered positive in this context, given the direction of fluid flow.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Some participants attempt to reconcile the direction of forces acting on the fluid with the flow direction, suggesting that P1A1 should be negative due to the opposing force from the pipe. Others propose that the force exerted by the pipe is necessary to maintain fluid flow, questioning the role of pressure and weight of the fluid.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the forces involved. Some have provided references for further reading, while others are seeking clarification on specific terms and concepts, such as Pascal's Law and the implications of changing cross-sectional areas in the pipe.

Contextual Notes

There appears to be confusion regarding the setup of the problem, particularly concerning the flow dynamics in a pipe with varying diameters. Participants are also addressing the implications of pressure forces acting on the fluid in relation to the control volume concept.

foo9008
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Homework Statement



The formula of the force exerted on the fluid by the pipe is P1A1 –Fx – P2A2 , I don’t understand why the P1A1 is positive ?

Homework Equations

The Attempt at a Solution



Assuming to the right is positive , shouldn’t the force acting on the water = -P1A1 ?

Because the water is flowing from left to right , the force acting on the water by the pipe should be in oppostite direction( which is –P1A1 ) , am I right ?
 
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foo9008 said:
I don’t understand why the P1A1 is positive ?
as water is flowing to the right force exerted by pipe on water should be left to right=its perhaps helping the water to maintain the flow
Things don't just start moving by themselves. There must be a force acting on the water in the pipe for it to move, and the obvious one is its own weight. Water is quite heavy stuff - a litre of it weighs a kilogram. The water in the tank pushes down on the water in the pipe.
what is your Fx ?
it appears your pipe diameter is changing!
 
drvrm said:
as water is flowing to the right force exerted by pipe on water should be left to right=its perhaps helping the water to maintain the flow
Things don't just start moving by themselves. There must be a force acting on the water in the pipe for it to move, and the obvious one is its own weight. Water is quite heavy stuff - a litre of it weighs a kilogram. The water in the tank pushes down on the water in the pipe.
what is your Fx ?
it appears your pipe diameter is changing!
if so , why F2 is in opposite direction ? according to you , F2 should help the water to flow , so it should in the same direction as the water flow , right ? which is directed to the right ?
 
foo9008 said:
f so , why F2 is in opposite direction ? according to you , F2 should help the water to flow , so it should in the same direction as the water flow , right ? which is directed to the right ?

in previous post i did'nt see the diagram of 'reducer'... i think the contraption is pushing water through a nozzle of reduced diameter and its not a 'streamline flow' arrangement - the change in momentum is being presented as a force Fx-
so the water at the nozzle is being pushed as a 'reaction' of the volume of water being pushed to the right- its a macro-model made by the set up;
its something like pushing burnt gas out of nozzle of rocket and a back thrust .
 
drvrm said:
in previous post i did'nt see the diagram of 'reducer'... i think the contraption is pushing water through a nozzle of reduced diameter and its not a 'streamline flow' arrangement - the change in momentum is being presented as a force Fx-
so the water at the nozzle is being pushed as a 'reaction' of the volume of water being pushed to the right- its a macro-model made by the set up;
its something like pushing burnt gas out of nozzle of rocket and a back thrust .
i still don't understand why the F1 is acting as the same direction of the low of water , can you explain further?
 
drvrm said:
as water is flowing to the right force exerted by pipe on water should be left to right=its perhaps helping the water to maintain the flow
Things don't just start moving by themselves. There must be a force acting on the water in the pipe for it to move, and the obvious one is its own weight. Water is quite heavy stuff - a litre of it weighs a kilogram. The water in the tank pushes down on the water in the pipe.
what is your Fx ?
it appears your pipe diameter is changing!
or do you mean since the diameter is decreasing along the pipe , so the F1 is to help the water flow (since there is not much obstruction ) , F2 is the force which try to prevent the water flow (since the water is difficult to move thru smaller diameter of pipe), so it is in opposite direction?
 
  • #11
The expression you gave is not the force exerted by the pipe on the fluid. Only -Fx is the force exerted by the pipe on the fluid. P1A1 is the force exerted by the fluid behind the control volume on the fluid in the control volume, and -P2A2 is the force exerted by the fluid ahead of the control volume on the fluid in the control volume. Since the cross sectional area has changed, there also should be a rate of change of momentum term on the other side of the equation.
 
  • #12
Chestermiller said:
The expression you gave is not the force exerted by the pipe on the fluid. Only -Fx is the force exerted by the pipe on the fluid. P1A1 is the force exerted by the fluid behind the control volume on the fluid in the control volume, and -P2A2 is the force exerted by the fluid ahead of the control volume on the fluid in the control volume. Since the cross sectional area has changed, there also should be a rate of change of momentum term on the other side of the equation.
Why F1 is behind the control volume? F2 is ahead of control volume?
 
  • #13
foo9008 said:
Why F1 is behind the control volume? F2 is ahead of control volume?
If there is pressure within the fluid, the fluid behind exerts a forward force on the fluid ahead of it, and the fluid ahead exerts a backward force on the fluid behind it.
 
  • #14
Chestermiller said:
If there is pressure within the fluid, the fluid behind exerts a forward force on the fluid ahead of it, and the fluid ahead exerts a backward force on the fluid behind it.
Why, can you explain??
 
  • #15
foo9008 said:
Why, can you explain??
Are you aware of Pascal's Law that, at a given location in a fluid, pressure acts equally (isotropically) in all directions?
 
  • #16
Chestermiller said:
Are you aware of Pascal's Law that, at a given location in a fluid, pressure acts equally (isotropically) in all directions?
Yes, how is the condition above link to pascal law
 
  • #17
foo9008 said:
Yes, how is the condition above link to pascal law
Is there pressure in the fluid that is situated behind the fluid in the control volume? According to Pascal's Law, does it push forward on the fluid within the control volume? Is there pressure in the fluid that is situated ahead of the fluid in the control volume? According to Pascal's Law, does it push backwards on the fluid within the control volume?
 
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