Why is potential energy considered negative in an inversed pendulum system?

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Discussion Overview

The discussion revolves around the treatment of potential energy in an inverted pendulum system, particularly focusing on the choice of coordinate system and the implications for the sign of potential energy. Participants explore how the reference point for potential energy affects calculations and interpretations.

Discussion Character

  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant notes that in their coordinate system, potential energy is expressed as PE=mgz, where z is negative due to the chosen upward direction.
  • Another participant questions where the textbook defines the zero point for height (h).
  • A subsequent reply indicates that the textbook sets the zero point of h at the point of rest of the pendulum, which is the same as the origin (O).
  • A later post mentions a correction related to the angle being negative, suggesting that this affects the work done by the pendulum.

Areas of Agreement / Disagreement

Participants express uncertainty regarding the reference point for potential energy and how it relates to the sign convention used in calculations. There is no clear consensus on the treatment of potential energy in this context.

Contextual Notes

There are unresolved aspects regarding the assumptions made about the coordinate system and the implications of the angle on the potential energy calculations.

Andrax
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we have an inversed pendulum(ignore the car)
cart.gif

and we choose the coordinate system to be upwards
the potential energy PE=mgz (z will be hegative since( O,k) is upwards right?) z is always under O.
but in the textbook they basically take the absolute value of h i don't understand why?
 
Last edited:
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Where is the textbook putting the zero of h?
 
ModusPwnd said:
Where is the textbook putting the zero of h?

at the point of rest of the pendulum (same as O)
 
fixed the problem (h ad to do with angle being negatgive which means the work of p is negative)
sorry my explication of the question was off , close this thread
 

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