Why is Root-2 in the Denominator of the Homework Solution?

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Homework Help Overview

The discussion revolves around a physics problem involving electric fields and unit vectors, specifically questioning the presence of root-2 in the denominator of a solution related to the electric field equations.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to understand the reasoning behind the inclusion of root-2 in the denominator. Some participants inquire about the expression of unit vectors from charge points to a specific location, while others provide partial expressions for the electric field.

Discussion Status

The discussion is ongoing, with participants exploring different aspects of the problem, including the setup of coordinate systems and the formulation of electric field equations. There is no explicit consensus yet, but guidance on unit vector expressions has been offered.

Contextual Notes

Participants emphasize the importance of a clear coordinate system for the problem, indicating that assumptions about the configuration may be under review.

sugz
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Homework Statement


Attached below

Homework Equations


E = [kq/r^2]r -------> r is the unit vector

The Attempt at a Solution


I did the same thing as the solution below, however, I do not understand why there is root-2 in the denominator. I would appreciate it if someone could explain this to me.
 

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How would you express the unit vector going from each Q to point P?
 
DelcrossA said:
How would you express the unit vector going from each Q to point P?
it would be E=[kQ/d^2]i
 
sugz said:
it would be E=[kQ/d^2]i

That's for one of the Q's. What about for the other one?

Note that it's essential to make sure you have set up a clear coordinate system for the problem.
 
It would be E=[kQ/2d^2](-cos45i+sin45j)
 

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