I Why is the Binding Energy of Deuterons So Low Compared to Larger Nuclei?

sarvesh upadhyay
Messages
5
Reaction score
0
Why the binding energy of deutron is very low?
 
Physics news on Phys.org
Why do you expect a higher binding energy?

It is an odd/odd nucleus.
 
  • Like
Likes sarvesh upadhyay
mfb said:
Why do you expect a higher binding energy?

It is an odd/odd nucleus.
Thanks for reply
Because average binding energy of nuclei is near about 7 Mev
 
Only for larger nuclei.
 
  • Like
Likes sarvesh upadhyay
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...
Back
Top