Why is the Electric Field outside this wire not zero?

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Homework Help Overview

The discussion revolves around understanding the behavior of electric fields in relation to conductors, particularly in the context of a long straight wire with charge density. Participants are exploring the implications of Gauss's law and the conditions under which electric fields are present or absent in different regions of a conductor.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are questioning the application of Gauss's law and whether the electric field should be zero outside the conductor. There is a discussion about the presence of electric fields at the surface and inside the conductor, as well as the implications of current flow on the electric field.

Discussion Status

There is an ongoing exploration of the concepts, with some participants expressing confusion about the conditions under which electric fields exist. Guidance has been offered regarding the distinction between different regions of the conductor and the effects of current flow, but no consensus has been reached.

Contextual Notes

Participants are grappling with the nuances of electric fields in conductors, particularly the assumption that there is no electric field inside a conductor in equilibrium, and how this applies to non-homogeneous conductors. The discussion reflects a mix of established principles and specific case considerations.

bryanso
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Homework Statement
Not a homework. Just want to understand a (should be simple) example.
Relevant Equations
Why is E not zero?
Not a homework. Just self-studying electromagnetism.

I am stuck at understanding the very beginning of the solution steps in this example:

The E as given in the solution is the field away from a long straight line with charge Lambda. That's clearly not the current configuration.

E should be zero by Gauss law, shouldn't it? ... Net charge is 0.

David Griffiths Electrodynamics 4th Edition, p. 368

Griffiths001.png
Griffiths002.png
 
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bryanso said:
E should be zero by Gauss law, shouldn't it? ... Net charge is 0.
Ask yourself: The field where?
 
> Ask yourself: The field where?

Outside is 0 from Gauss Law.

Inside conductor is 0 (after equilibrium).

So there are two fields, one on the outer surface and one on the inside contacting surface?

Am I in the right direction?
 
The fields are only at the surface?? Please be a little more complete in your description. Electric field lines start on a positive charge and end on a negative charge.
 
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bryanso said:
> Ask yourself: The field where?

Outside is 0 from Gauss Law.

Inside conductor is 0 (after equilibrium).

So there are two fields, one on the outer surface and one on the inside contacting surface?

Am I in the right direction?
What about E field between a and b? By Gauss' law?
 
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Thank you all. Got it. I knew I missed something very simple. I got misled by the general rule of thumb that there is no E inside a conductor. But this is not a homogenous conductor here. I can proceed now.

Thanks
 
bryanso said:
Thank you all. Got it. I knew I missed something very simple. I got misled by the general rule of thumb that there is no E inside a conductor. But this is not a homogenous conductor here. I can proceed now.

Thanks
Right. There can be no E field inside a conductor.
In fact, unless it's a perfect NON-conductor there can be no E field in the steady-state.

UNLESS there is current flow, in which case you have E = ρι where ρ is resistivity and ι is current density.
(Vector equation.)

 

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