- #1
homeworkhelpls
- 41
- 1
i integrated y to get (1/3x^3 + 2x) with upper limit 5 / lower limit 2 but got 45 not 175 / 3
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Why Is the Integral Result 175/3 Instead of 45?
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SUMMARY
The integral of the function (1/3)x^3 + 2x evaluated from the lower limit of 2 to the upper limit of 5 results in 45, not 175/3. The discrepancy arises when the lower limit is incorrectly set to -2, which would yield 175/3. This indicates a potential error in the problem statement or a calculation mistake. Additionally, proper notation is crucial; writing (1/3)x^3 clarifies that x^3 is in the numerator, preventing misinterpretation.
PREREQUISITES- Understanding of definite integrals
- Familiarity with polynomial functions
- Knowledge of proper mathematical notation
- Experience with computational tools like Wolfram Alpha
- Review the fundamentals of definite integrals in calculus
- Practice integrating polynomial functions
- Learn about common notation pitfalls in mathematical expressions
- Explore the use of Wolfram Alpha for verifying integral calculations
Students studying calculus, educators teaching integration techniques, and anyone interested in verifying integral calculations accurately.
i integrated y to get (1/3x^3 + 2x) with upper limit 5 / lower limit 2 but got 45 not 175 / 3
- #2
- 29,427
- 21,147
Both Wolfram Alpha and I agree with you.homeworkhelpls said:
- #3
Maarten Havinga
- 76
- 42
Me too!
- #4
Ibix
Science Advisor
- 13,471
- 16,090
The integral would evaluate to 175/3 if the lower limit were x=-2. I suspect a silly typo or calculation slip by the question setter.
Last edited:
- #5
YouAreAwesome
Gold Member
- 70
- 33
Just a notation tip. 1/3x^3 can be misread as 1/(3x^3) placing the x^3 in the denominator. To be precise, we can instead write (1/3)x^3 to ensure x^3 is in the numerator and not mistakenly placed in the denominator.homeworkhelpls said:
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