Why Is the Magnetic Field in the Z Direction in This Mutual Induction Problem?

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SUMMARY

The discussion centers on the mutual induction problem involving solenoids and the orientation of the magnetic field. The magnetic field is directed in the z-direction because the coordinate system is aligned with the solenoid's axis. The mutual inductance, denoted as M, is derived from its definition and Faraday's law, specifically using the formula M_{12}=\frac{N_2\phi _{12}}{I_1}. The emf is calculated based on the changing magnetic flux through the loop, which is essential for understanding the mutual induction process.

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here is the question and solution:
http://i29.tinypic.com/30cy4cn.jpgi can't understand certain things in here:
i can't understand the 3d picture.
why the magnetic field in the z direction??

i can't understand how did they find the mutual inductance here.
because by this formula

M_{12}=\frac{N_2\phi _{12}}{I_1}

in our situation we need to find the current in the celonoid
but they for some weird reason find the emf
and right after without any calculation
they show the mutual induction coeff

why??
 
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They set up their co-ordinate system so that the z-axis runs parallel to the solenoids axis, that's why the field points in the z-direction.

As for M, it comes straight from its definition, together with Faraday's law:

\Phi_{\text{loop}}=MI_{\text{solenoid}}\implies \varepsilon_{\text{loop}}=-\frac{d\Phi_{\text{loop}}}{dt}=-M\frac{d I_{\text{solenoid}}}{dt}
 
thank :)
 

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