Why Is the Magnetic Vector Potential Azimuthal Inside an Infinite Solenoid?

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The magnetic vector potential inside an infinite solenoid is azimuthal due to the symmetry of the magnetic field generated by the solenoid's current. The formula A(r) = ∫(J(r')/r) dτ becomes problematic because the solenoid extends infinitely, complicating the integration. To determine the vector potential A, one can first calculate the magnetic field B using the integral form of Ampère's law. Once B is established, A can be inferred by recognizing that B is the curl of A. This approach simplifies the process of finding A in this specific configuration.
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Why is the magnetic vector potential of a point inside a infinite soleniod azimuthal assuming the axis of solenoid is the z axis.
Problem is the formulae A(\vec r)=\int_{v} \frac {\vec J(\vec r^{'})}{r} d\tau doesn't hold any more due to the infinite extent of the current
 
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When you say "why is" I assume you mean "what is", and A is simple to find in this case because you can find B using the integral form of ampere's law and then guess A by looking at B = Curl(A).
 
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