Why is the minus sign omitted in the voltage across the inductor?

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    Inductor Voltage
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The discussion centers on the omission of the minus sign in the voltage across an inductor, despite Faraday's law stating emf = -d(flux)/dt. The voltage is often expressed as v = d(flux)/dt to simplify calculations, particularly when only the magnitude is needed. Lenz's law explains that the induced emf opposes the change that produces it, justifying the sign convention. When an inductor is in series with a battery and the switch is opened, the voltage across the inductor helps maintain current despite decreasing flux. Ultimately, Kirchhoff's law reinforces that the total voltage drops in a circuit must equal zero.
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According to faraday's law the governing equation is emf=-d(flux)/dt.But we usually write the voltage across the inductor as v=d(flux)/dt.What happened to the minus sign?
 
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If there's an inductor in series with a battery and you open the switch, the flux will be decreasing yet the voltage that appears across the inductor in a sense that will 'maintain' the current. I think that (Lenz's law) accounts for the choice of sign.
 
It is used to indicate that the induced emf OPPOSES the change producing it.
If you only need to calculate the magnitude is is common to drop the - sign
 
Kirchhoff's law states the the sum of the voltage drops around the circuit must equal zero.
 
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