Why is the net torque not exactly zero.

In summary: If you recalculate the table for torques about 0 cm, but with the outer hangers at 1 cm and 99 cm, the net torque would be zero.
  • #1
snagglepuffin
4
0

Homework Statement


The sum of the net torques is zero even f the numerical result is not. Rather than simply explaining that the net torque is close to zero, justify that your net torque is small, within the context of this experiment.


2. Attached is a pdf of the lab that we had this week. My question is regarding Question 2 on Page 5.


Here is what we got for our measurements.
DATA TABLE 1
Mass (kg) Force (N) Sign of torque Moment Arm (m) Torque (N-m)
Meter stick .1974 -1.93 - .49 -.9457
Hanger 1 .020 -.196 - .66 -.1294
Hanger 2 .0207 -.203 - .98 -.1989
Hanging Mass .0999 -.797 - .66 -.6461
Force sensor no mass 1.98 + .98 1.92
Sum of forces : -1.328N
Sum of torques : 0.02 N-m



The Attempt at a Solution


My lab partner and I were trying to figure out why our measured net torque was not zero, but .02 N-m. We thought that it might have been the use of significant figures, but that did not work. Also, through observation of the setup, we noticed that the meter stick was not hanging perfectly straight, because of the hangers. We thought that there was a torque along the x-axis. Assume that the x-axis runs the length of the meter stick and the y-axis is vertical.

Any other ideas out there why our calculated net torque is not exactly zero?
 

Attachments

  • torque_.pdf
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  • #2
snagglepuffin said:
through observation of the setup, we noticed that the meter stick was not hanging perfectly straight, because of the hangers.
Was there a reason you couldn't adjust the force scale to get the meter stick to be horizontal?

One experiement should have been to only use hangar 2 at the 100 cm end of the meter stick, which would simplify the test and perhaps be used to "calibrate" the test. I'm wondering about the actual net effect of a support or hangar placed at the ends of a meter stick, where each net force could actually act as if it originates somewhat inside the ends of the meter stick. Can the support / hangars be positioned partially beyond the ends of the meter stick in an attempt to get the actual net force to act at almost exactly at the 0 and 100 cm points, although this may not explain why the calculated torque was .02 N m.
 
Last edited:
  • #3
rcgldr said:
Was there a reason you couldn't adjust the force scale to get the meter stick to be horizontal?

The meter stick was about 1mm off on the horizontal, so overall it was level horizontally.

The hangers themselves would not hold it perfectly vertical. I tried multiple hangers and picked the best ones, but there was still some twisting down the meter stick. If you look at the end of the meter stick and it is perfectly straight, you should only see the (3/8)" x 1" profile. Looking down our meter stick I could see the other end, leading me to believe that there is an unaccounted for torque about the x-axis.

Also, the closest the supports could be to the end of the meter stick was 1cm. Could the fact that there was still mass on the other side of the hanger be where the error is?
 
  • #4
snagglepuffin said:
Also, the closest the supports could be to the end of the meter stick was 1cm. Could the fact that there was still mass on the other side of the hanger be where the error is?
What happens if you recalculate the table for torques about 0 cm, but with the outer hangers at 1 cm and 99 cm? (In this case the hanger at 1 cm generates a tiny amount of torque).
 
  • #5


I would like to first acknowledge that it is rare for any measurement to be exactly zero. In this experiment, we are dealing with multiple variables and sources of error, which can contribute to a non-zero net torque.

One possible explanation for the non-zero net torque is the presence of friction in the experiment. Friction can cause a force that is perpendicular to the direction of motion, which can result in a non-zero torque. This could be especially relevant in the case of the hanging mass, as it is being pulled downwards by gravity and may experience some friction on the meter stick.

Another factor to consider is the precision of our measurements. While we may have used significant figures, there may still be some inherent uncertainty in our measurements that could contribute to a non-zero net torque. This could be due to the sensitivity of the equipment or human error in recording the measurements.

Additionally, as you mentioned, the positioning of the meter stick may also play a role in the non-zero net torque. The hangers may cause the meter stick to tilt slightly, leading to a torque along the x-axis as you suggested. This could be further exacerbated by any imperfections in the meter stick itself, such as uneven weight distribution or slight bends.

In conclusion, there are multiple factors that could contribute to a non-zero net torque in this experiment. It is important to carefully consider and account for these potential sources of error in order to improve the accuracy and precision of our measurements.
 

1. Why is the net torque not exactly zero in a balanced system?

Net torque is defined as the sum of all individual torques acting on an object. In a balanced system, the individual torques cancel each other out, resulting in a net torque of zero. However, in real-life situations, it is impossible to completely eliminate all external forces and factors that can affect torque, so the net torque may not be exactly zero.

2. What factors can contribute to a non-zero net torque?

There are several factors that can contribute to a non-zero net torque, such as friction, air resistance, and imperfections in the object's shape or weight distribution. These external forces can create a slight imbalance in the system, resulting in a non-zero net torque.

3. How does the distance of the force from the axis of rotation affect the net torque?

The distance between the applied force and the axis of rotation, also known as the lever arm, plays a crucial role in determining the net torque. The longer the lever arm, the greater the torque. This is because a longer lever arm creates a larger perpendicular distance between the force and the axis of rotation, resulting in a greater turning effect.

4. Can a net torque be negative?

Yes, a net torque can be negative. This occurs when the individual torques acting on an object are in opposite directions, resulting in a net torque that is in the opposite direction of the rotational motion. In other words, the object may rotate in the opposite direction as intended.

5. How does the distribution of mass affect the net torque?

The distribution of mass in an object can greatly impact the net torque. If the mass is evenly distributed, the net torque will be zero. However, if the mass is concentrated on one side of the object, it will create an imbalance and result in a non-zero net torque. This is why it is essential to evenly distribute weight in objects that require balanced rotation.

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